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krek1111 [17]
3 years ago
8

The stroke that begins a point in volleyball is​

Physics
1 answer:
natka813 [3]3 years ago
3 0
The stroke that begins a point in volleyball is called a serve
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A rocket travels at a speed of 14,000 m/s. What is the distance travelled by the rocket in 150s?
kati45 [8]

1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):

v=\frac{S}{t}

Rearranging the equation, we can write

S=vt

In this problem, v=14000 m/s and t=150 s, so the distance travelled by the rocket is

S=vt=(14000 m/s)(150 s)=2.1 \cdot 10^6 m


2) We can solve the second part of the problem by using the same formula we used previously. This time, t=300 s, so we have:

S=vt=(14000 m/s)(300 s)=4.2 \cdot 10^6 m/s

5 0
4 years ago
A very small object with mass 8.30×10-9 kg and positive charge 6.90×10-9 C is projected directly toward a very large insulating
Rainbow [258]

Answer:

41.4496148484\ m/s

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

\sigma = Surface charge density = 5.9\times 10^{-8}\ C/m^2

\Delta x = 0.57-0.26

q = Charge = 6.9\times 10^{-9}\ C

m = Mass of object = 8.3\times 10^{-9}\ kg

Electric field due to a sheet is given by

E=\dfrac{\sigma}{2\epsilon_0}\\\Rightarrow E=\dfrac{5.9\times 10^{-8}}{2\times 8.85\times 10^{-12}}\\\Rightarrow E=3333.33\ V/m

Electric field is given by

E=\dfrac{V}{d}

Voltage is given by

V=E\Delta x

Kinetic energy is given by

K=qV

\dfrac{1}{2}mv^2=qE\Delta x\\\Rightarrow v=\sqrt{\dfrac{2qE\Delta x}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 6.9\times 10^{-9}\times 3333.33\times (0.57-0.26)}{8.3\times 10^{-9}}}\\\Rightarrow v=41.4496148484\ m/s

The initial speed of the object is 41.4496148484\ m/s

7 0
3 years ago
The physical (natural) laws which establish how things work can be investigated by the scientific method. True or False
UNO [17]

Answer:

True

Explanation:

It's a bit hard to explain, so you can watch a youdube video on it or something.

8 0
3 years ago
Read 2 more answers
Two cars, C and D, travel in the same direction on a long, straight section of highway. During a particular time interval Ato, c
a_sh-v [17]

Answer:

possibly because the car is running out of gas

Explanation:

6 0
4 years ago
a bus travels 4 km due north and 3 km due west going from bus station a to bus station b. the magnitude of the bus displacement
ladessa [460]

Answer:

5km

Explanation:

Magnitude of displacement is found by getting the resultant. Resultant is same as the bypotenuse hence

R=\sqrt {{x^{2}+y^{2}} where x is the displacement in west direction and y is displacement in North direction. Substituting x with 3km and y with 4 km then

R=\sqrt {{3^{2}+4^{2}}=5km

4 0
3 years ago
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