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Vlad [161]
3 years ago
14

What must always be the same on both sides of a chemical equation?

Chemistry
1 answer:
Margaret [11]3 years ago
5 0

The number of Atoms must be the same on both sides

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Temperature is used to measure the movement of particles such as atoms and molecules. As temperature increases, what is true of
ch4aika [34]
This is thermodynamics. When you increase the temperature of an object, the particles gain on kinethic energy ergo the move faster. When you decrease it, they slow down.
6 0
3 years ago
Read 2 more answers
Isotope Atomic Mass (amu) Percent Abundance
exis [7]

Answer:

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

Explanation:

Given data:

Atomic mass of silicon= ?

Percent abundance of Si-28 = 92.21%

Atomic mass of Si-28 = 27.98 amu

Percent abundance of Si-29 = 4.70%

Atomic mass of  Si-29 = 28.98 amu

Percent abundance of Si-30 = 3.09%

Atomic mass of  Si-30 = 29.97 amu

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)+(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (92.21×27.98)+(4.70×28.98)+(3.09×29.97) /100

Average atomic mass =  2580.04 +136.21+92.61 / 100

Average atomic mass = 2808.86 / 100

Average atomic mass  = 28.08amu.

The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.

7 0
3 years ago
Read 2 more answers
What is the molar mass for FeBr3
AleksAgata [21]
Mass of Iron (Fe): 55.845Mass of Bromine (Br): 79.904
You need to multiply the mass of Br by 3 because there are 3 Bromine atoms. 
(79.904)(3)+ 55.845= 239.712+55.845                                = 295.557 g/mol

6 0
3 years ago
A materials scientist has created an alloy containing aluminum, copper, and zinc, and wants to determine the percent composition
liubo4ka [24]

Answer:

0.8749 grams of hydrogen gas was formed from the reaction.

Explanation:

P = Pressure of hydrogen gad= 744 Torr = 0.98 atm

(1 atm = 760 Torr)

V = Volume of hydrogen gas= 11 L

n = number of moles of hydrogen gas= ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of vapor = 27.0 °C = 300.15 K

Putting values in above equation, we get:

Using an ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.98 atm\times 11 L}{0.0821 L atm/mol K\times 300.15 K}

n = 0.4374 moles

Mass of 0.4374 moles of hydrogen gas:

0.4374 mol × 2 g/mol = 0.8749 g

0.8749 grams of hydrogen gas was formed from the reaction.

7 0
3 years ago
A prototype is usually different from the final product
Assoli18 [71]
True. The prototype is usually the "rough draft" the figure out what needs fixed or upgraded before they make the final product "final draft". Hope that helped!
7 0
3 years ago
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