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Slav-nsk [51]
3 years ago
10

How do I calculate how many meters are in 7.2 light years?

Physics
1 answer:
Vikentia [17]3 years ago
5 0

Answer:

68.2 Quadrillion meters

Explanation:

A lightyear is the distance that light travels in one year.

Speed of light is 3*10^8\ m/s

So light covers 300,000,000 meters in one second.

One year has 31536000 seconds so , light covers

9.461*10^{15}\  meters\ in\ one\ year

so 7.2 light years is

7.2*(9.461*10^{15})\\6.82*10^{16}

so 7.2 light years is

6.82 x 10^(16) meters or

68.2 Quadrillion meters

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Answer:

a.     F = 2.32*10^-18 N

b.     The force F is 2.59*10^11 times the weight of the electron

Explanation:

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vo: initial speed of the electron = 4.00*10^5 m/s

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x: distance traveled by the electron = 5.40cm = 0.054m

you solve the equation (2) for a and replace the values of the parameters:

a=\frac{v^2-v_o^2}{2x}=\frac{(6.60*10^5m/s)^2-(4.00*10^5m/s)^2}{2(0.054m)}\\\\a=2.55*10^{12}\frac{m}{s^2}

Next, you use the second Newton law to calculate the force:

F=ma

m: mass of the electron = 9.11*10^-31kg

F=(9.11*10^{-31}kg)(2.55*10^{12}m/s^2)=2.32*10^{-18}N

The magnitude of the force exerted on the electron is 2.32*10^-18 N

b. The weight of the electron is given by:

F_g=mg=(9.11*10^{-31}kg)(9.8m/s^2)=8.92*10^{-30}N

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\frac{F}{F_g}=\frac{2.32*10^{-18}N}{8.92*10^{-30}N}=2.59*10^{11}

The force F is 2.59*10^11 times the weight of the electron

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Which functions of water in living systems would still be possible if water was not polar and did not form hydrogen bonds
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Answer:

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a is the acceleration

s is the displacement

Here we have:

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