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Butoxors [25]
3 years ago
8

One of the difficulties in studying mechanics is that many common words are used with highly specific technical meanings,among t

hem velocity, acceleration, position, speed, and displacement. The series of questions in this problem is designed to getyou to try to think of these quantities like a physicist.Answer the questions in this problem using words from the following list: A. position B. direction C. displacement D. coordinates E. velocity F. acceleration G. distance H. magnitude I. vector J. scalar K. components
Part A Velocity differs from speed in that velocity indicates a particle's __________ of motion.Enter the letter from the list given in the problem introduction that best completes the sentence.
Part B Unlike speed, velocity is a __________ quantity.Enter the letter from the list given in the problem introduction that best completes the sentence.
Part C A vector has, by definition, both __________ and direction.Enter the letter from the list given in the problem introduction that best completes the sentence.
Part D Once you have selected a coordinate system, you can express a two-dimensional vector using a pair of quantities known collectively as __________.Enter the letter from the list given in the problem introduction that best completes the sentence. D Part E Speed differs from velocity in the same way that __________ differs from displacement.
Physics
1 answer:
Allisa [31]3 years ago
8 0

Mnanan anaw anwkkww wjakana akkqna akaoaman akamakq

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According to the general theory of relativity, what are consequences of the curvature of space-time? Check all that apply. The d
Svetlanka [38]

Answer:

The dilation of time.

The falling of objects.

The changing of paths of light.

Explanation:

I have explained in the image attached below.

From the explanation, the correct ones are;

The dilation of time.

The falling of objects.

The changing of paths of light.

4 0
3 years ago
A 0.3-m-radius automobile tire rotates how many revolutions after starting from rest and accelerating at a constant 2.13 rad/s2
Aloiza [94]

Answer:

The automobile tire rotates 91 revolutions

Explanation:

Given;

angular acceleration of the automobile, α = 2.13 rad/s²

time interval, t = 23.2-s

To calculate the number of revolutions, we apply the first kinematic equation;

\theta = \omega_i  \ + \frac{1}{2} \alpha t^2

the initial angular velocity is zero,

\theta =0\ + \frac{1}{2} (2.13) (23.2)^2\\\\\theta = 573.2256 \ Rad

Find how many revolutions that are in 573.2256 Rad

N = \frac{\theta}{2 \pi} = \frac{573.2256}{2\pi} \\\\N = 91 \ revolutions

Therefore, the automobile tire rotates 91 revolutions

3 0
4 years ago
A car driving down the road speeds up to pass bus. While passing changed velocity from 10 m/s to 35 m/s in 5 seconds. What is th
VMariaS [17]

Answer:

The ans is 3

Explanation:

First write the given values and write the formula of acceleration than do velocity - final velocity by time taken is 10-35%5 so, therefore acceleration of car is 3

5 0
3 years ago
Listed below are the measured radiation absorption rates​ (in W/kg) corresponding to 11 cell phones. Use the given data to const
Fantom [35]

Answer:

The 5-number summary is

1. Median = 0.93 W/kg

2. Lower quartile = 0.69 W/kg

3. Upper quartile = 1.16 W/kg

4. Minimum value = 0.54 W/kg

5. Maximum value = 1.42 W/kg

Explanation:

We are given the measured radiation absorption rates​ (in W/kg) corresponding to 11 cell phones.

1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57

What is 5-number summary?

A 5-number summary refers to a box plot that basically shows 5 statistical characteristics of a data set.

These statistical characteristics are:    

1. Median

2. Lower quartile

3. Upper quartile  

4. Minimum value  

5. Maximum value  

1. Median:

Arrange the data in ascending order

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

(n+1)/2 gives the median value of the data set.

(11 + 1)/2 = 6th position

Therefore, 0.93 W/kg is the median of the data set.

2. Lower quartile:

Divide the data set into two equal halfs (include median in both if n = odd)

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The lower quartile is the median of the lower half of the data set.

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

The median is 6/2 = 3rd position

Therefore, the lower quartile of the data set is 0.69 W/kg

3. Upper quartile:

Divide the data set into two equal halfs (include median in both if n = odd)

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The upper quartile is the median of the lower half of the data set.

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The median is 6/2 = 3rd position

Therefore, the upper quartile of the data set is 1.16 W/kg

4. Minimum value:

The minimum value is the least value in the data set.

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

Therefore, the minimum value of the data set is 0.54 W/kg

5. Maximum value  

The maximum value is the least value in the data set.

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

Therefore, the maximum value of the data set is 1.42 W/kg

The box plot is illustrated in the attached diagram.

6 0
3 years ago
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