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Butoxors [25]
3 years ago
8

One of the difficulties in studying mechanics is that many common words are used with highly specific technical meanings,among t

hem velocity, acceleration, position, speed, and displacement. The series of questions in this problem is designed to getyou to try to think of these quantities like a physicist.Answer the questions in this problem using words from the following list: A. position B. direction C. displacement D. coordinates E. velocity F. acceleration G. distance H. magnitude I. vector J. scalar K. components
Part A Velocity differs from speed in that velocity indicates a particle's __________ of motion.Enter the letter from the list given in the problem introduction that best completes the sentence.
Part B Unlike speed, velocity is a __________ quantity.Enter the letter from the list given in the problem introduction that best completes the sentence.
Part C A vector has, by definition, both __________ and direction.Enter the letter from the list given in the problem introduction that best completes the sentence.
Part D Once you have selected a coordinate system, you can express a two-dimensional vector using a pair of quantities known collectively as __________.Enter the letter from the list given in the problem introduction that best completes the sentence. D Part E Speed differs from velocity in the same way that __________ differs from displacement.
Physics
1 answer:
Allisa [31]3 years ago
8 0

Mnanan anaw anwkkww wjakana akkqna akaoaman akamakq

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The force of Earth's gravity on a capsule in space will lessen as it moves farther away. If the capsule moves to twice its dista
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Answer: One quarter of the force

Explanation:

According to Newton's law of Gravitation, the force F exerted between two bodies of masses m1 and m2  and separated by a distance r  is equal to the product of their masses and inversely proportional to the square of the distance:

F=G\frac{(m1)(m2)}{r^2}    (1)

Where Gis the gravitational constant

This means that the gravity force decreases when the distance between these two bodies increases.

In this context, if the distance between the capsule and the Earth increases twice, the new distance will be 2r.

Substituting this distance in (1):

F=G\frac{(m1)(m2)}{(2r)^2}    (2)

F=G\frac{(m1)(m2)}{4r^2}    

<u>Finally:</u>

F=\frac{1}{4}G\frac{(m1)(m2)}{r^2} >>>This means the force toward Earth becomes one quarter "weaker"

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