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3 years ago

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Type of gingival infection is characterized by necrosis of gingival papillae?

1 answer:

Brut [27]3 years ago

8 0

<span>Characterized by necrosis of gingival tissues, periodontal ligament, and alveolar bone. Associated with HIV infections and immunosuppressive therapies. Severe and rapid periodontal destruction. Alveolar bone loss, resulting in lack of deep packet formation. </span>

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What is the agent that causes frost wedging?

LuckyWell [14K]

Answer:

Freeze wedging is caused by the repeated freeze-thaw. Frost wedging occurs as the result of 9% expansion of water when it is converted to ice. Cracks filled with water are forced further apart when it freezes.

4 0

3 years ago

As the atomic number ___________(Increases/Decreases) within a period, the atomic radius _______(Increases/Decreases).

Alex777 [14]

Answer:

Atomic radius is the distance from the atom's nucleus to the outer edge of the electron cloud. In general, atomic radius decreases across a period and increases down a group.

Explanation: you should mark me brainliest

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3 years ago

One mole of H2 S o4 contains off 4.22 into 10 raise to power 24 atoms is it true or false

zalisa [80]

Answer:

False. One mole of a certain substance will always contain $6.002 \cdot 10^{23}$ atoms of that substance.

Explanation:

Hope this helped!

5 0

3 years ago

Read 2 more answers

Al2(SO4)3(s) + H2O(l) ---- Al2O3(s) + H2SO4 (aq) calculate enthalpy formation for this reaction. Balance the reaction. Calculate

katen-ka-za [31]

The given chemical equation is:

$Al_{2}(SO_{4})_{3}(aq)+H_{2}O(l)-->Al_{2}O_{3}(aq)+H_{2}SO_{4}(aq)$

On balancing the equation we get,

$Al_{2}(SO_{4})_{3}(aq)+3H_{2}O(l)-->Al_{2}O_{3}(aq)+3H_{2}SO_{4}(aq)$

Calculating enthalpy of formation of this reaction from the standard heats of formation of the products and reactants:

Δ $H_{reaction}^{0}=[H_{f}^{0}(Al_{2}O_{3}(s)) + (3*H_{f}^{0}(H_{2}SO_{4}(aq))] - [H_{f}^{0}(Al_{2}SO_{4}(aq)) + (3*H_{f}^{0}(H_{2}O(l))]$

=[(-1669.8kJ/mol)+ {3* (-909.27 kJ/mol)}]-[(-3442kJ/mol)+{3*(-285.8 kJ/mol)}]

=[(-4397.61kJ/mol)]-[(-4299.4kJ/mol)]

=-98.21kJ/mol

Total enthalpy change when 15 mol of $Al_{2}(SO_{4})_{3}$ reacts will be=

$15 mol Al_{2}(SO_{4})_{3}*\frac{-98.21kJ}{1 molAl_{2}(SO_{4})_{3}} =-1473.15kJ/mol$

4 0

4 years ago

A 544 mg of a mixture of fluorene and benzoic acid was weighed out and subjected to an extraction and recrystallization. After t

butalik [34]

<u>Answer:</u> The percent composition of fluorene is 33.08 % and benzoic acid is 36.03 %.

<u>Explanation:</u>

We are given:

Mass of mixture = 544 mg

Mass of fluorene after purification = $1.80\times 10^2mg=180mg$

Mass of benzoic acid after purification = 196 mg

To calculate the percentage composition of a substance in a mixture, we use the equation:

$\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100$

<u>For fluorene:</u>

$\%\text{ composition of fluorene}=\frac{180}{544}\times 100=33.08\%$

Hence, the percent composition of fluorene is 33.08 %

<u>For benzoic acid:</u>

$\%\text{ composition of benzoic acid}=\frac{196}{544}\times 100=36.03\%$

Hence, the percent composition of benzoic acid is 36.03 %

5 0

4 years ago