Answer:
Friction: is used to hang an object on the wall
Force: is what will determine if the object stays in place or not
Explanation:
Answer: The Earth's layer, which has the covering and layer, is made of a progression of things, or structural plates, that creep after some time. Along these lines, at intersecting limits, mainland outside is made and maritime covering is devastated. 2 plates slippy past each other structures a redesign plate limit.
Answer:
a. 1222.13 J b. 2.36 m. His new position is above his original position
Explanation:
From work-kinetic energy principle, workdone = change in kinetic energy
So work the skateboarder does on himself W₁ = -116 J
work done by friction W₂ = -264 J
gravitational potential energy change W₃ = mgΔy
The kinetic energy change ΔK = 1/2m(v² - u²) where m = mass of skater = 52.9 kg, u = initial speed of skaterboarder = 2.04 m/s and v = final speed of skaterboarder = 6 m/s. ΔK = 1/2m(v² - u²) = ΔK = 1/2 × 52.9(6² - 2.4²) = 842.13 J
So, W₁ + W₂ + W₃ = ΔK
W₃ = ΔK - W₁ - W₂ = 842.13 J - (-116 J) - (-264J) = 842.13 J + 116 J + 264J = 1222.13 J
b. Since W₃ = mgΔy = 1222.13 J
Δy = W₃/mg = 1222.13/(52.9 × 9.8) = 1222.13/518.42 = 2.36 m
Since Δy > 0, his new position is above his original position.
Answer:
9.0 m
Explanation:
Applying
V = kq/r......................... Equation 1
Where V = Electric potential, q = charge, r = distance, k = Coulomb's constant.
make r the subject of the equation
r = kq/V................... Equation 2
From the question,
Given: q = 1.00×10⁻⁵ C, V = 10000 V
Constant: k = 9.0×10⁹ N⋅m²/C²
Substitute these values into equation 2
r = (9.0×10⁹×1.00×10⁻⁵)/10000
r = 9.0 m
For decrease: it’s the first and last one and for increase it’s the middle two