Ask question

Ask question

All categories

3 years ago

13

For a continuous and oriented fiber-reinforced composite, the moduli of elasticity in the longitudinal and transverse directions

are 19.7 and 3.66 GPa, respectively. If the volume fraction of fibers is 0.25, determine the moduli of elasticity of fiber and matrix.

1 answer:

goldfiish [28.3K]3 years ago

6 0

Answer:

attached below

Explanation:

You might be interested in

Global climate and weather patterns are driven by differences in the amount of heat energy in different areas of the earth. Whic

Verizon [17]

The Earth receives different amounts of solar energy in different regions.

8 0

3 years ago

Primary U.S. interstate highways are numbered 1-99. Odd numbers (like the 5 or 95) go north/south, and evens (like the 10 or 90)

Gekata [30.6K]

Answer:

The Java code is given below with appropriate variable names and tags for better understanding

Explanation:

import java.util.Scanner;

public class LabProgram{

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int highwayNumber;

int primaryNumber;

highwayNumber = scnr.nextInt();

if(highwayNumber<1 || highwayNumber>999)

System.out.println(highwayNumber+" is not a valid interstate highway number.");

else{

if(highwayNumber>=1 && highwayNumber<=99){

System.out.print("The "+highwayNumber+" is primary, going ");

if(highwayNumber%2==1)

System.out.println("north/south.");

else

System.out.println("east/west.");

}

else{

primaryNumber = highwayNumber%100;

System.out.print("The "+highwayNumber+" is auxillary, serving the "+primaryNumber+", going ");

if(primaryNumber%2==1)

System.out.println("north/south.");

else

System.out.println("east/west.");

}

}

}

}

6 0

3 years ago

10 10 10 10 10 10 10 10 10 10

s2008m [1.1K]

Answer:

10

Explanation:

5 0

3 years ago

Read 2 more answers

All areas of the country use a BAC of 0.100.10 g/dL as the legal intoxication level. Is it possible that the mean BAC of all dr

vlabodo [156]

Answer:

C. Yes, and it is highly probable.

Explanation:

Null hypothesis, $H_0$ : ц 0.09

Alternative hypothesis, $H_1$ : ц > 0.09

Test statistic is,

x Z = x - ц / s

$\frac{0.15 - 0.09 }{0.06}$

$\frac{0.06}{0.06}$

=1

The p-value is,

p = P(Z > z)

=1—P(Z ≤1)

= 1— 0.841345

= 0.158655

(From normal tables)

The p-value is greater than the significance level, so we fail to reject the null hypothesis. The correct option is, C

Yes, and it is highly probable.

6 0

3 years ago

An oscillating mechanism has a maximum displacement of 3.2m and a frequency of 50Hz. At timet-0 the displacement is 150cm. Expre

Helen [10]

Given:

max displacement, A = 3.2 m

f= 50 Hz

at t = 0, displacement, d = 150 cm = 1.5 m

Solution:

Displacement in the general form is represented by:

d = Asin(ωt ± α)

d = 3.2sin(2πft ± α)

d = 3.2sin(100πt ± α)

where,

A = 3.2 m,

ω = 2πf = 100π

Now,

at t = 0,

1.5 = 3.2sin(100π(0) ± α )

1.5 = 3.2sinα

sin α = $\frac{1.5}{3.2}$ = 0.4687

α = $sin^{-1}(0.46875)$ = 27.95° = 0.488 radian

Now, we can express displacement in the form of 'Asin(wt + α)' as:

d = 3.2sin(100πt ± 0.488 )

6 0

3 years ago