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sveticcg [70]
3 years ago
12

Is gravity a property of mass ?

Physics
2 answers:
Alja [10]3 years ago
7 0

Answer:

Explanation:Gravity is the attraction between two objects that have mass. The amount of gravity is directly proportional to the amount of mass of the objects and inversely proportional to the square of the distance between the objects. Gravity is a force that increases the velocity of falling objects - they accelerate.

Alex787 [66]3 years ago
5 0

Answer:

no it is not a property of mass

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A graph of a wave is shown if the frequency f is 8.0 Hz what is the waves speed
defon

Answer:

C

6 =  \frac{3}{2} \lambda \\  wavelength :  \:  \lambda = 4 \: m \\ from \: wave \: equation \\ v = f\lambda  \\ v = 8 \times 4 \\ v = 24 \:  {ms}^{ - 1}

6 0
3 years ago
(a) Draw a Velocity - Time graph for an Object with Constant Acceleration.
den301095 [7]

Explanation:

answers to 1 and 2 above/below respectively but can't do 3 because I don't know what graph you're talking about

7 0
2 years ago
A 98-kg fullback is running along at 8.6 m / s when a 76-kg defensive back running in the same direction at 9.8 m / s jumps on h
algol13
The total momentum before and after the collision must be conserved.

The total momentum before the collision is:
p_i = m_1 v_1 + m_2 v_2
where m1 and m2 are the masses of the two players, and v_1 and v_2 their initial velocities. Both are considered with positive sign, because the two players are running toward the same direction.

The final momentum is instead
p_f = (m_1+m_2)v_f
because now the two players are moving together with a total mass of (m1+m2) and final speed vf.

By requiring that the momentum is conserved
p_i=p_f
we  can calculate vf, the post-collision speed:
m_1 v_1 + m_2 v_2 = (m_1+m_2)v_f
v_f =  \frac{m_1 v_1 + m_2 v_2}{m_1 +m_2}= \frac{(98 kg)(8.6 m/s)+(76 kg)(9.8m/s)}{98 kg+76 kg}=9.1 m/s
and the direction is the same as the direction of the players before the collision.
6 0
3 years ago
The concrete slab of a basement is 11 m long, 8 m wide, and 0.20 m thick. During the winter, temperatures are nominally 17°C and
mina [271]

Answer:

\frac{dQ}{dt}= 4312 W

Explanation:

As we know that base of the slab is given as

A = 11 \times 8

A = 88 m^2

now we know that rate of heat transfer is given as

\frac{dQ}{dt} = \frac{kA}{x} (T_2 - T_1)

here we know that

k = 1.4 W/m k

Also we have

x =0.20

\frac{dQ}{dt} = \frac{1.4(88)}{0.20}(17 - 10)

\frac{dQ}{dt}= 4312 W

7 0
3 years ago
Ethan made a diagram to compare examples of the first and second laws of thermodynamics. What belongs in the areas marked X and
Thepotemich [5.8K]

<u>First law of thermodynamics:</u>

  • It states that <em>"Energy neither be created nor it can be destroyed". </em>simply it converts one form of energy into another form.
  • It is also known as<em> "law of conservation of energy"</em>

<u>Limitations of First law</u>

  1. It doesn't provide a clear idea about the direction of transfer of heat.
  2. It doesn't provide the information that how much heat energy converted inti work.
  3. Its not given any practical applications.

<u>II law of thermodynamics:</u>

It states that <em>"the total entropy of the system can never decrease over time"</em>

It is strongly proved by two laws, they are

<em>1. Kelvin-plank statement:</em>

      He stated that "any engine does not give 100% efficiency". It violates the Perpetual motion of machine II kind<em>(PMM-II).</em>

<em>2. Classius statement: </em>

<em>    </em><em>    It states that "Heat always flows from high temperature body to low temperature body, without aid of external energy". </em>

<em>          Also it stated that " Heat can also be transferred from low temperature body to high temperature body, by the aid of an external energy".</em>

<em>Applications of II law: </em>

<em>Refrigeration &Air conditioning, Heat transfer, I.C. engines, etc.</em>

3 0
3 years ago
Read 2 more answers
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