They use a spectrograph so the answer would be B.
167•F which is c
Tell me my wrong from right
Answer:
300 J
Explanation:
First of all, we need to calculate the net force acting on the crate, which is given by:

where
F = 100 N is the horizontal push
is the force of friction
Substituting,

Now we can calculate the net work done on the crate:

where
d = 10 m is the displacement
Substituting,

According to the work-energy theorem, the kinetic energy gained by the crate is equal to the work done on it: therefore, the answer is 300 J.
First, let's list everything we have...
a = 1.83 m/s^2
F = 1870 N (converted from kN to N)
vi = 0 m/s (it says started from rest, therefore velocity starts at 0)
t = 16 s
1). "Force acting on the car" is a bit ambiguous because there are many forces. But I'm going to assume that they are looking for just a basic implementation of force equation:

where:
F = force
m = mass
a = acceleration
2). I recommend memorizing your equations of motion, because once you know them this part is also just as easy:

where:
vf = final velocity
vi = initial velocity
a = acceleration
t = time