Chloe’s teacher gives her and her lab partner soil samples from different parts of the city: the park, the area next to a pond,
1 answer:
You might be interested in
First, we have to remember the molarity formula:
Part 1:
In this case, our solute is sodium nitrate (NaNO3), and we have the mass dissolved in water, then we have to convert grams to moles. For that, we need the molecular weight:
Then, we calculate the moles present in the solution:
Now, we have the necessary data to calculate the molarity (with the solution volume of 200 mL):
The molarity of this solution equals 0.2339 M.
Part 2:
In this case, we have the same amount (in moles and mass) of sodium nitrate, but a different volume of solution, then we only have to change it:
So, the molarity of this solution is 0.1701 M.
The question is incomplete, here is the complete question.
When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from a mixture of 3.0g Ag and 3.0g .
Answer : The mass of silver sulfide is produced from a mixture is 3.44 grams.
Explanation : Given,
Mass of Ag = 3.0 g
Mass of = 3.0 g
Molar mass of Ag = 107.8 g/mole
Molar mass of = 256 g/mole
Molar mass of = 247.8 g/mole
First we have to calculate the moles of Ag and .
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 16 mole of react with 1 mole of
So, 0.0278 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 16 mole of react to give 8 mole of
So, 0.0278 moles of react to give
moles of
Now we have to calculate the mass of
Therefore, the mass of silver sulfide is produced from a mixture is 3.44 grams.