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Virty [35]
3 years ago
9

Related Rates: the hypotenuse of an isosceles right triangle is increasing at a rate of 2mm/s. at what rate is the area of the t

riangle increasing when the length of one of the equal sides is 10mm? Related Rates: the hypotenuse of an isosceles right triangle is increasing at a rate of 2mm/s. at what rate is the area of the triangle increasing when the length of one of the equal sides is 10mm?
Physics
1 answer:
NISA [10]3 years ago
7 0
The answer is <span>It is increasing at </span><span>2<span>√2</span><span> mm/s.

Below is the solution:

</span></span>Call the length of the legs x<span> and the hypotenuse </span>z<span>, then we have </span><span><span>z2</span>=2<span>x2</span></span><span>(Pythagorean Theorem)
</span>
We know that the rate of change of x<span> with respect to time, </span>t<span>, is </span><span><span><span>dx/</span><span>dt</span></span>=2</span><span> mm/s.
</span>
We want to find <span><span>dz/</span><span>dt</span></span><span> at the instant when </span><span>x=10</span><span> mm
</span>
Differentiate <span><span>z2</span>=2<span>x2</span></span><span> implicitly with respect to time, </span>t<span>:
</span>
<span>d/<span>dt</span></span><span>(<span>z2</span>) </span>= <span>d/<span>dt</span></span><span>(2<span>x2</span><span>)
</span></span>2z <span><span>dz/</span><span>dt </span></span>= 4x <span><span>dx/</span><span>dt
</span></span>z <span><span>dz/</span><span>dt </span></span>= 2x <span><span>dx/</span><span>dt

</span></span>z=10<span>√2</span> mm
<span>10<span>√2</span> mm)</span><span><span>dz/</span><span>dt </span></span>= 2<span>(10 mm)</span><span>(2 mm/s<span>)

</span></span><span><span>dz/</span><span>dt </span></span>= 2<span>√2</span><span> mm/s</span>
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<h3>Answer:</h3>

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<h3>Explanation:</h3>

<u>We are given;</u>

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We are required to determine the force that must be applied by the woman so the brick does not fall.

  • We need to importantly note that;
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<h2>30 J</h2>

Explanation:

The work done by an object can be found by using the formula

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