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harkovskaia [24]
3 years ago
5

ASAP HELP!!!!!!!!!!

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
6 0
I think it would be the bread
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Which property is NOT a physical property?
Ede4ka [16]

Answer:

im pretty sure color is the right one

5 0
3 years ago
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A person tries to heat up her bath water by adding 5.0 L of water at 80°C to 60 L of water at 30°C. What is the final temperatur
Ratling [72]

Answer:T_f=33.85\°C

Explanation:

Hello,

In this case, we can write the following relationship, explaining that the lost by the hot water is gained by the cold water:

Q_{hot,W}=-Q_{cold,W}

Which in terms of mass, specific heat and temperatures, we have:

m_{hot,W}Cp_{W}(T_f-T_{hot,W})=-m_{cold,W}Cp_{W}(T_f-T_{cold,W})

Whereas the specific heat of water is cancelled out to obtain the following temperature, considering that the density of water is 1 kg/L:

T_f=\frac{m_{hot,W}T_{hot,W}+m_{cold,W}T_{cold,W}}{m_{hot,W}+m_{cold,W}}\\\\T_f=\frac{5.0kg*80\°C+60kg*30\°C}{5.0kg+60kg} \\\\T_f=33.85\°C

Regards.

4 0
3 years ago
22. A piece of wood board contains approximately 6.76 X 1023 molecules of wood, C2H4920, how
Licemer1 [7]

Answer:

<h2>1.23 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{6.76 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{6.76}{6.02}  \\  = 1.22923...

We have the final answer as

<h3>1.23 moles</h3>

Hope this helps you

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What is the correct formula for Heptarsenic Tetrabromide
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4 years ago
Calculate a mass of 12.044×10^23 of calcium carbonate​
tigry1 [53]

0.02 g of calcium carbonate (CaCO₃)

Explanation:

To solve the question we use the Avogadro's number using the following reasoning:

if         1 moles of calcium carbonate contains 6.022 × 10²³ units of calcium carbonate

then   X moles of calcium carbonate contains 12.044 × 10²³ units of calcium carbonate

X = (1 ×  12.044 × 10²³) / 6.022 × 10²³ = 2 moles of calcium carbonate

mass = number of moles × molecular weight

mass of calcium carbonate (CaCO₃) = 2 / 100 = 0.02 g

Learn more about:

Avogadro's number

brainly.com/question/13928106

#learnwithBrainly

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