Answer:
0.96 gcm¯³
Explanation:
From the question given above, the following data were obtained:
Mass of empty beaker = 103 g
Mass of beaker + water = 361 g
Mass of beaker + oil = 351 g
Density of water = 1 gcm¯³
Density of cooking oil =?
Next, we shall determine the mass of water. This can be obtained as follow:
Mass of empty beaker = 103 g
Mass of beaker + water = 361 g
Mass of water =?
Mass of water = (Mass of beaker + water) – (Mass of empty beaker)
Mass of water = 361 – 103
Mass of water = 258 g
Next, we shall determine the volume of the beaker. This can be obtained by calculating the volume of water in the beaker.
Density of water = 1 gcm¯³
Mass of water = 258 g
Volume of water =?
Density = mass /volume
1 = 258 / volume
Cross multiply
1 × volume = 258
Volume of water = 258 cm³
Thus the volume of the beaker is 258 cm³.
Next, we shall determine the mass of the cooking oil. This can be obtained as follow:
Mass of empty beaker = 103 g
Mass of beaker + oil = 351 g
Mass of cooking oil =?
Mass of cooking oil = (Mass of beaker + oil) – (Mass of empty beaker)
Mass of cooking oil = 351 – 103
Mass of cooking oil = 248 g
Finally, we shall determine the density of the cooking oil. This can be obtained as follow:
Mass of cooking oil = 248 g
Volume of the beaker = 258 cm³
Density of cooking oil =?
Density = mass / volume
Density = 248 / 258
Density of cooking oil = 0.96 gcm¯³
