A jet engine pushes air at high velocity toward the rear of the plane. Thrust is created moving the plane forward. Which stateme
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Both carts experience the same force but Cart A has a greater speed after the recoil.
The given parameters;
- <em>Mass of the cart A = 0.4 kg</em>
- <em>Mass of the cart B = 0.8 kg</em>
Apply the principle of conservation of linear momentum to determine the velocity of the carts after collision;
According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.
Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
a) p₂ = 1.88 kg*m/s
θ = 273.4 º
b) Kf = 37% of Ko
Explanation:
a)
- Assuming no external forces acting during the collision, total momentum must be conserved.
- Since momentum is a vector, their components (projected along two axes perpendicular each other, x- and y- in this case) must be conserved too.
- The initial momenta of both particles are directed one along the x-axis, and the other one along the y-axis.
- So for the particle moving along the positive x-axis, we can write the following equations for its initial momentum:
- We can do the same for the particle moving along the positive y-axis:
- Now, we know the value of magnitude of the final momentum p1, and the angle that makes with the positive x-axis.
- Applying the definition of cosine and sine of an angle, we can find the x- and y- components of the final momentum of the first particle, as follows:
- Now, the total initial momentum, along these directions, must be equal to the total final momentum.
- We can write the equation for the x- axis as follows:
- We know from (3) that p₀₂ₓ = 0, and we have the values of p₀1ₓ from (1) and pf₁ₓ from (5) so we can solve (7) for pf₂ₓ, as follows:
- Now, we can repeat exactly the same process for the y- axis, as follows:
- We know from (2) that p₀1y = 0, and we have the values of p₀₂y from (4) and pf₁y from (6) so we can solve (9) for pf₂y, as follows:
- Since we have the x- and y- components of the final momentum of the second particle, we can find its magnitude applying the Pythagorean Theorem, as follows:
- We can find the angle that this vector makes with the positive x- axis, applying the definition of tangent of an angle, as follows:
- The angle that we are looking for is just the arc tg of (12) which measured in a counter-clockwise direction from the positive x- axis, is just 273.4º.
b)
- Assuming that both masses are equal each other, we find that the momenta are proportional to the speeds, so we find that the relationship from the final kinetic energy and the initial one can be expressed as follows:
- So, the final kinetic energy has lost a 37% of the initial one.