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Iteru [2.4K]
3 years ago
8

A jet engine pushes air at high velocity toward the rear of the plane. Thrust is created moving the plane forward. Which stateme

nt is correct about the amount of force the air pushes the engine forward with?
The air pushes the engine with an equal force in the opposite direction. The air pushes the engine with a much smaller force in the same direction.
The air pushes the engine with an equal force in the same direction. The air pushes the engine with a much smaller force in the opposite direction.
Physics
1 answer:
Lapatulllka [165]3 years ago
5 0
The air pushes the engine with an equal force in the opposite direction.
Whenever force is used there is an opposite yet equal affect.
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A solution of phosphoric acid was made by dissolving 10.0 g H3PO4 in 100.0 mL water. The resulting volume was 104 mL. Calculate
OLEGan [10]

Answer:

density is 1.057 g/mL

mole fraction is 0.0180

molarity is 0.98 mol/L

mole fraction is 0.0180

Explanation:

Given data

acid mass = 10 g

water volume = 100 mL

total volume = 104 mL

density = 1 g/cm³

to find out

the density, mole fraction, molarity, and molality

solution

first we calculate the density that is = total mass g / volume of solution mL

total mass = mass of H3PO4 + water  mass

so water mass = density x volume

water mass = 100 ml x 1.0  g/cm3

water mass = 100 g  

so total mass  = 110.00 g

so that

density = total mass g / volume of solution mL

density = 110 / 104 = 1.057 g/mL

now we calculate no of moles in solvent i.e = mass  H2O / mlar mass H2O

no of moles in solvent = 100/18.015 = 5.55 moles

and no of moles in solute i.e = mass of H3PO4 / mlar mass in H3PO4

moles in solute i.e = 10/ 97.994 = 0.102 moles

so total moles is  5.55  + 0.102 = 5.652 moes

so now mole fraction = no of moles in solute / total moes

mole fraction = 5.55 / 5.65

mole fraction is 0.0180

now we calculate first

mole fraction in solute and solvent that is

mole fraction in solute = no of moles in solute/ total moles

mole fraction in solute = 0.102 /5.65

mole fraction in solute is 0.0180

and mole fraction in solvent that = no of moles in solvent/ total moles

mole fraction in solvent that = 5.55/ 5.65

mole fraction in solvent that is 0.982

so molarity = no of moles of solute / volume

molarity = 0.102/0.104

molarity is 0.98 mol/L

and molality  is = no of moles of solute / mass

molality = 0.102 / 100

molality  is  1.02 mol/kg

6 0
3 years ago
4) How many liters are in 9.23*10^19 molecules of oxygen gas?
Lapatulllka [165]

0.0034L

Explanation:

Given parameters:

Number of molecules of oxygen gas = 9.23 x 10¹⁹molecules

Unknown:

Volume of oxygen =  ?

Solution:

Assuming the gas is at standard temperature and pressure conditions;

 Volume of gas = number of moles x 22.4

we need to find the number of moles of the oxygen gas;

   number of moles = \frac{number of particles}{6.02 x 10[tex]^{23}}[/tex]

 Number of moles = \frac{9.23 x [tex]10^{19}}{6.02 x 10^{23}}[/tex]

Number of moles = 1.53 x 10⁻⁴moles

Volume of gas =  1.53 x 10⁻⁴ x 22.4 = 0.0034L

learn more:

STP brainly.com/question/12684384

#learnwithBrainly

3 0
3 years ago
Calculate the force applied to raise a table to a height of 8m if 120j of work was done
Ray Of Light [21]

The force applied to raise a table to a height of 8m when 120 Joules of work is done is 15 N. That is, Force F = 15N

<h3>What is Work ?</h3>

Work is the product of force and distance in the direction of force. Work is done on an object when the displacement of the object is in the direction of the force applied. That is,

W = F x S

The S.I unit of work is Joule.

Given that a table to a height of 8m and 120J of work was done. To find the force applies, the parameters to consider are

  • Work W = 120 J
  • Distance S = 8 m
  • Force F = ?

Make force F the subject of formula from the formula written above. That is,

F = W/S

F = 120 / 8

F = 15 N

Therefore, if the 120 Joule of work is done, the force applied to raise a table to a height of 8m is 15 Newtons.

Learn more about Work here: brainly.com/question/25573309

#SPJ1

7 0
2 years ago
On dry concrete, a car can decelerate at a rate of 7.00 m/s2 , whereas on wet concrete it can decelerate at only 5.00 m/s2 . Fin
MariettaO [177]

Answer:

Explanation:

a ) Let the distance required in former case be d₁ .

initial velocity u = 30 m /s , final velocity v =0 , deceleration a = 7.00 m /s²

v² = u² - 2 a s

0 = 30² - 2 x 7 x d₁

d₁ = 64.28 m

b) initial velocity u = 30 m /s , final velocity v =0 , deceleration a = 5.00 m /s²

v² = u² - 2 a s

0 = 30² - 2 x 5 x d₂

d₂ = 90  m

c)

t = .5 s

s₁  = ut - .5 at²

= 30 x .5 - .5 x 7 x .5²

= 15 - .875

= 14.125 m

t = .5 s

s₂  = ut - .5 at²

= 30 x .5 - .5 x 5 x .5²

= 15 - .625

= 14.375  m

3 0
4 years ago
What is the mass of 2.47 moles of<br> carbon dioxide CO2 ?
Anna11 [10]

Answer:

CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).

So first finding the mass of 1 molecule of CO2 which is equals to

= mass of 1 carbon atom + masses of 2 oxygen atom, we get

= 12+(16*2)= 12+32= 44 a.m.u.

Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )

1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams

So our answer is 110 grams

6 0
3 years ago
Read 2 more answers
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