Answer:
The answer to your question is 245.9 g of Fe₂O₃
Explanation:
Data
grams of Fe₂O₃ = ?
grams of Fe = 172 g
Balanced chemical reaction
Fe₂O₃ + 3H₂ ⇒ 2Fe + 3H₂O
Process
1.- Calculate the molar mass of of Iron Oxide and Iron
Fe₂O₃ = (2 x 56) + (3 x 16) = 112 + 48 = 160 g
2Fe = 2 x 56 = 112 g
2.- Use proportions and cross multiplication to solve this problem
160 g of Fe₂O₃ --------------- 112 g of Fe
x ---------------- 172 g of Fe
x = (172 x 160)/112
x = 27520/112
x = 245.9 g of Fe₂O₃
Answer:
11
Explanation:
electronic configuration = 1s^2, 2s^2, 2p^6, 3s^1
therefore total electrons = 2+2+6+1 = 11
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Answer:
The first one
Explanation:
I can't read them well: it should be 
** this is the expanded version
Answer:
m= 6.9905 = 7 g
Explanation:
The formula is m= M.n
m= mass (g), M= Molar mass (g/mole), n= moles (moles)
Molar mass of Cu is 63.55
=) m= 63.55*0.11
m= 6.9905 = 7 g
B 2
is which shell are the valence electrons of the elements in period 2 found
