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vitfil [10]
3 years ago
10

The sound intensity level 5.0 m from a point source is 95 dB. At what distance will it be 75 dB?

Physics
1 answer:
DochEvi [55]3 years ago
5 0

Answer:

47.86 or 50 m

Explanation:

Source = 95 + (20log(5) + 10log(4pi)) = 119.96 dB

75 - 119.96 + 10log(4pi) = -33.61

-33.61/-20 = log(distance)

10^1.68 = distance = 47.86m

47.86 or 50 m is the correct ans

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A centrifuge in a medical laboratory rotates at an angular speed of 3,650 rev/min. when switched off, it rotates through 48.0 re
AlladinOne [14]
First of all we need to convert everything into SI units.

Let's start with the initial angular speed, \omega _i = 3650 rev/min. Keeping in mind that
1 rev = 2 \pi rad
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we have
\omega _i = 3650  \frac{rev}{min} \cdot  \frac{2 \pi rad/rev}{60 s/min} =382.0 rad/s

And we should also convert the angle covered by the centrifuge:
\theta = 48.0 rev= 48.0 rev \cdot  2 \pi  \frac{rad}{rev}=301.4 rad

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2aS = v_f^2 -v_i^2
of an uniformly accelerated motion but for a rotational motion. It will be
2 \alpha \theta = \omega_f^2-\omega_i^2
And by substituting the numbers, we can find the value of \alpha, the angular acceleration:
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4 0
3 years ago
A car has a force of 2000N and a mass of<br> 1000kg. What is the acceleration of the<br> car?
yan [13]

Answer:

100

Explanation:

by dividing 2000N and 1000kg.

5 0
4 years ago
The distance between two planets is 1600 km. How much time would the light
Snowcat [4.5K]

Answer:

5.33*10^-3 seconds

Explanation:

c = d/t

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d = distance (1600 km)

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3.0*10^5 = 1600/t

t = 1600/3.0*10^5

t = 5.33*10^-3 seconds

I hope this helped! :)

6 0
4 years ago
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