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Law Incorporation [45]
3 years ago
8

Why does a shirt appear white outside on a sunny day?

Physics
2 answers:
Maru [420]3 years ago
8 0
The shirt absorbs the sunlight, so it appears white. All the light is reflected, so the shirt appears white. The sunlight refracts when it hits the shirt, so the shirt appears white.
Gemiola [76]3 years ago
6 0

Answer:

The shirt absorbs sunlight, so it looks white. All of the light is reflected, so then the shirt appears white. The sunlight refracts when it hits the shirt, so the shirt appears white.

Explanation:

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As a 5.0 × 10^2-newton basketball player jumps
AysviL [449]
     This player is initially at rest, then the Force Weight (W) and the Normal Force (N) have a same module. When applies a Extra Force (E) on the floor, this reacts with this increase, causing the player to be released upwards.
     Using the Newton's Secound Law, we have:

F_{R}=ma \\ W+E-N=ma \\ N =W+E \\ N=5*10^2+10*10^2 \\ \boxed {N=1.5*10^3N}

Number 3

If you notice any mistake in my english, please let me know, because i am not native.
4 0
3 years ago
An ideal photo-diode of unit quantum efficiency, at room temperature, is illuminated with 8 mW of radiation at 0.65 µm wavelengt
nadya68 [22]

Answer:

I = 4.189 mA    V = 0.338 V

Explanation:

In order to do this, we need to apply the following expression:

I = Is[exp^(qV/kT) - 1]   (1)

However, as the junction of the diode is illuminated, the above expression changes to:

I = Iopt + Is[exp^(qV/kT) - 1]   (2)

Now, as the shunt resistance becomes infinite while the current becomes zero, we can say that the leakage current is small, and so:

I ≅ Iopt

Therefore:

I ≅ I₀Aλq / hc  (3)

Where:

I₀A = Area of diode (radiation)

λ: wavelength

q: electron charge (1.6x10⁻¹⁹ C)

h: Planck constant (6.62x10⁻³⁴ m² kg/s)

c: speed of light (3x10⁸ m/s)

Replacing all these values, we can get the current:

I = (8x10⁻³) * (0.65x10⁻⁶) * (1.6x10⁻¹⁹) / (6.62x10⁻³⁴) * (3x10⁸)

I = 4.189x10⁻³ A or 4.189 mA

Now that we have the current, we just need to replace this value into the expression (2) and solve for the voltage:

I = Is[exp^(qV/kT) - 1]

k: boltzman constant (1.38x10⁻²³ J/K)

4.189x10⁻³ = 9x10⁻⁹ [exp(1.6x10⁻¹⁹ V / 1.38x10⁻²³ * 300) - 1]

4.189x10⁻³ / 9x10⁻⁹ = [exp(38.65V) - 1]

465,444.44 + 1  = exp(38.65V)

ln(465,445.44) = 38.65V

13.0508 = 38.65V

V = 0.338 V

6 0
3 years ago
Describe the changes in the velocity of a ball thrown straight up into the air. then describe the changes in the ball's accelera
expeople1 [14]

There is a displacement. Just because the ball is thrown up, and not crossways, doesn't mean its location is not moving. Remember, positive displacement is together a displacement in the direction east, right, and up.  The velocity is the distance over time. To compute that, you must look how high the ball moved before falling back down. Acceleration is expected to be constant at 9.80m/s^2. That is the force of gravity. But remember that you are disregarding air friction when you are computing the acceleration.

7 0
3 years ago
Calculate the number of vacancies per cubic meter in gold (au) at 900c. the energy for vacancy formation is 0.98 ev/atom. furthe
Sergeeva-Olga [200]
My mom said its f so i think its q

8 0
2 years ago
Cocaine, which is derived from the coca leaf, is grown mostly in Colombia and its neighboring countries while heroin, which is d
nevsk [136]

Answer:

Because of the location, humidity and temperatures.

Explanation:

Coca is grown in humid and very humid subtropical forests, called yungas and

they form the lower floor of the upper Jungle, in the Central Andes, mostly in Peru and Bolivia. The  yungas are in contact with the rainforests of the lowlands in Amazonia, where it has been  started to expand coca cultivation recently (Dourojeanni, 1988). The optimum altitude is 1000 a  2000 meters (where cocaine content is higher), with optimal annual average precipitation, is 2000 meters  mm, but it is grown between 700 and 2000 msnm and with an average annual rainfall of 1000 to 4200 mm.

msnm = meters above sea level

6 0
3 years ago
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