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o-na [289]
3 years ago
7

A device contains an electric circuit, powered by a battery, that provides light energy and heat energy. It is a

Physics
2 answers:
Daniel [21]3 years ago
4 0

Answer : The device is a Flash light.

Explanation :

A device contains an electric circuit, powered by a battery, that provides light energy and heat energy. It is a Flash light.

It is a closed circuit powered by a battery. The LED or incandescent light bulb is the source of light in flash light.

It consists of a reflector, battery and a switch.

Hence, the correct answer is Flash light.

olga2289 [7]3 years ago
3 0
A flashlight does that.
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A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and ret
emmasim [6.3K]

f' = frequency observed by the police car after sound reflected from the vehicle and comes back to police car = 1250 Hz

f = frequency emitted by the police car  = 1200 Hz

V = speed of sound = 340 m/s

v = speed of vehicle = ?

frequency observed by the police car is given as

f' = f (V + v)/(V - v)

inserting the values in the above equation

1250 = 1200 (340 + v)/(340 - v)

v = 6.9 m/s

4 0
3 years ago
Read 2 more answers
How much voltage is in the primary coil if there are 3200 windings in the
Lesechka [4]

Answer:

Voltage in primary coil is 3.91 V

Explanation:

For transformer we know that the working principle is given as

\frac{V_1}{V_2} = \frac{N_1}{N_2}

here we know that

V_1 [tex] = voltage in primary coil[tex]V_2 = 25 V

N_1 = 500

N_2 = 3200

Now we have

\frac{V_1}{25} = \frac{500}{3200}

V_1 = 3.91 V

8 0
3 years ago
Determine the weight of an average physical science textbook whose mass is 3.1 kilograms. The acceleration due to gravity is 9.8
Mrrafil [7]

Given:

mass is 3.1 kilograms

The acceleration due to gravity is 9.8m/s2

 

Required:

Weight

 

Solution:

W = mg

W = (3.1 kilograms)( 9.8m/s2)

W = 30.38 Newtons

5 0
2 years ago
A 50kg person standing still in ice skates throws their helmet to the right at 25 m/s while on a frictionless surface. This give
labwork [276]

Answer:

2.0 kg

Explanation:

5 0
3 years ago
How far apart (in mm) must two point charges of 70.0 nC (typical of static electricity) be to have a force of 1.30 N between the
Sever21 [200]

Answer:r=5.824 mm

Explanation:

Given

Charge q_1=70 nC

q_2=70 nC

Force between them F=1.30 N

Electrostatic Force is given by

F=\frac{kq_1q_2}{r^2}

where q_1 and q_2 are the charge on the Particles

r=distance between them

k=Coulomb\ constant =9\times 10^9 N-m^2/C^2

1.3=\frac{9\times 10^9\times 70\times 70\times 10^{-18}}{r^2}

r^2=\frac{9\times 10^9\times 70\times 70\times 10^{-18}}{1.3}

r=\sqrt{33.923\times 10^{-6}}

r=5.824\times 10^{-3}

r=5.824 mm

5 0
3 years ago
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