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2 years ago

Find the graph of the inequality y<= -1/3+1

Mathematics

1 answer:

Dafna11 [192]2 years ago

4 0

Here. This is the graph you wanted. The underside is shaded by the way.

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(08.01)

Aleksandr-060686 [28]

The list is needed in order to solve the problem, Im sorry but I can’t do anything with this information

5 0

2 years ago

A place from this table is chosen at random. Let event A = The place is a city.

Crank

Answer:

Final answer is $P(A^c)=\frac{3}{7}$

Step-by-step explanation:

We have been given a table containing a list of few places that are either city or in North America.

Total number of places in that list = 7

That means sample space has 7 possible events.

Given that a place from this table is chosen at random. Let event A = The place is a city.

Now we need to find about what is $P(A^c)$ .

That means find find the probability that chosen place is not a city.

there are 3 places in the list which are not city.

Hence favorable number of events = 3

Then required probability is given by favorable/total events.

$P(A^c)=\frac{3}{7}$

6 0

3 years ago

If a person can carry 40 pounds, and a group of people want to carry 86 pounds of stuff, how many people are necessary to carry

aliina [53]

Answer:

3 people

Step-by-step explanation:

Because 40+40 =80 also equals 2 people so if they can only do 80 together then you would need another person even if its 6 more pounds then 80.

Hope this helps....Also please like if this helped you so I know to do more!!! :)

4 0

3 years ago

Devin has a snake. The snake eats one mouse every week which Devin purchases from the local pet store. If m represents the cost

n200080 [17]

Assuming it's not a leap year,
then there are 365 days a year.
This is about 52 weeks.
The cost of a mouse is 52m

4 0

3 years ago

Money Flow The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the

77julia77 [94]

Answer:

Present value = $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5% compounded continuously

Now,

Accumulated Value of the money flow = $1000e^{0.05t}$

The present value of the money flow = $\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt$

= $1000\int\limits^4_0 {e^{0.015t}} \, dt$

= $1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4$

= $1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]$

= 1000 × [70.7891 - 66.6667]

= $4,122.4

Accumulated interest = $e^{rt}\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t}} \, dt$

= $e^{0.035\times4}\times4,122.4$

= $4,742

8 0

3 years ago