आप शोर मत करिए। किस प्रकार का वाक्य है- *

A 85.0kg man and a 65, 0kg woman are riding a Ferris wheel with a radius of 20.0m. What is the Ferris wheels tangential velocity

zvonat [6]

Answer:

The Ferris wheel's tangential (linear) velocity if the net centripetal force on the woman is 115 N is 3.92 m/s.

Explanation:

Let's use Newton's 2nd Law to help solve this problem.

F = ma

The force acting on the Ferris wheel is the centripetal force, given in the problem: $F_c=115 \ \text{N}$ .

The mass "m" is the sum of the man and woman's masses: $85+65= 150 \ \text{kg}$ .

The acceleration is the centripetal acceleration of the Ferris wheel: $a_c=\displaystyle \frac{v^2}{r}$ .

Let's write an equation and solve for "v", the tangential (linear) acceleration.

$\displaystyle 115=m(\frac{v^2}{r} )$
$\displaystyle 115 = (85+65)(\frac{v^2}{20})$
$\displaystyle 115=150(\frac{v^2}{20} )$
$.766667=\displaystyle(\frac{v^2}{20} )$
$15.\overline{3}=v^2$
$v=3.9158$

The Ferris wheel's tangential velocity is 3.92 m/s.

8 0

2 years ago

Describe how varying the incline plane angle Affects the force

Greeley [361]

Answer: the force increases as the angle increases

Explanation:

If we assume the incline plane is frictionless, the only force acting on an object on the incline plane is the force of gravity:

$F=mg$

where m is the mass and g the acceleration due to gravity.

However, the actual force that makes the object sliding down along the incline is not the gravity itself, but the component of the force of gravity parallel to the surface of the incline, which is given by

$F_p = mg sin \theta$

where $\theta$ is the angle of the incline.

Therefore, we see that as the angle of the incline increases, the force on the object increases.

4 0

4 years ago

Water with a volume flow rate of 0.001 m3/s, flows inside a horizontal pipe with diameter of 1.2 m. If the pipe length is 10m an

galben [10]

Answer:

$\triangle P=1.95*10^{-4}$

Explanation:

Mass $m=0.001$

Diameter $d=1.2m$

Length $l=10m$

Generally the equation for Volume flow rate is mathematically given by

$Q=AV$

$V=\frac{Q}{\pi/4D^2}$

$V=\frac{0.001}{\pi/4(1.2)^2}$

$V=8.84*10^{-4}$

Generally the equation for Friction factor is mathematically given by

$F=\frac{64}{Re}$

Where Re

Re=Reynolds Number

$Re=\frac{pVD}{\mu}$

$Re=\frac{1000*8.84*10^{-4}*1.2}{1.002*10^{-3}}$

$Re=1040$

Therefore

$F=\frac{64}{Re}$

$F=\frac{64}{1040}$

$F=0.06$

Generally the equation for Friction factor is mathematically given by

$Head loss=\frac{fLv^2}{2dg}$

$H=\frac{0.06*10*(8.9*10^-4)^2}{2*1.2*9.81}$

$H=19.9*10^{-9}$

Where

$H=\frac{\triangle P}{\rho g}$

$\triangle P=\frac{19.9*10^{-9}}{10^3*(9.81)}$

$\triangle P=H*\rho g$

$\triangle P=1.95*10^{-4}$

6 0

4 years ago

Does water expand more as the temperature drops even more below 0 deg? I am worried about the coolant in my rad. as the temp.is

alex41 [277]

Water is, indeed, an exception. Normally when temperature drops, material shrinks. Water doesn't, water expands instead.

4 0

4 years ago

Elenna [48]

Answer:

They are both unsegmented worms

Also:

They are both multicellular, invertebrates, heterotrophs, bilateral symmetry

Hope this Helps

5 0

3 years ago

आप शोर मत करिए। किस प्रकार का वाक्य है- *​

आप शोर मत करिए। किस प्रकार का वाक्य है- *