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Masteriza [31]
3 years ago
11

आप शोर मत करिए। किस प्रकार का वाक्य है- *​

Physics
1 answer:
Law Incorporation [45]3 years ago
7 0

Answer:

477547748jkdsjdjk

Explanation:

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Detailed solution is given below

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3 years ago
The boy moving down the hill posses what energy?​
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Answer:    Kinetic energy

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Kinetic energy and potential energy can change forms. For example, the car moving up the hill is kinetic energy

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a hydraulic machine can be used to lift extremely heavy objects. why is the fluid in the hydraulic machine a liquid rather than
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A water pipe having a 4.00 cm inside diameter carries water into the basement of a house at a speed of 1.00 m/s and a pressure o
posledela

Answer:

8.16\ \text{m/s}

Explanation:

d_1 = Initial diameter = 4 cm

v_1 = Initial velocity = 1 m/s

d_2 = Final diameter = 7.8 m

v_2 = Final velocity

A = Area = \pi\dfrac{d^2}{4}

From the continuity equation we get

A_1v_1=A_2v_2\\\Rightarrow \pi\dfrac{d_1^2}{4}v_1=\pi\dfrac{d_2^2}{4}v_2\\\Rightarrow v_2=\dfrac{d_1^2}{d_2^2}v_1\\\Rightarrow v_2=\dfrac{4^2}{1.4^2}\times 1\\\Rightarrow v_2=8.16\ \text{m/s}

The speed of water at the second floor is 8.16\ \text{m/s}.

8 0
3 years ago
Two resistances, R1 and R2, are connected in series across a 12-V battery. The current increases by 0.500 A when R2 is removed,
KATRIN_1 [288]

Answer:

a)   R₁ = 14.1 Ω,   b)  R₂ =  19.9 Ω

Explanation:

For this exercise we must use ohm's law remembering that in a series circuit the equivalent resistance is the sum of the resistances

all resistors connected

           V = i (R₁ + R₂)

with R₁ connected

           V = (i + 0.5) R₁

with R₂ connected

           V = (i + 0.25) R₂

We have a system of three equations with three unknowns for which we can solve it

We substitute the last two equations in the first

           V = i ( \frac{V}{ i+0.5} + \frac{V}{i+0.25} )

           1 = i ( \frac{1}{i+0.5} + \frac{1}{i+0.25} )

           1 = i ( \frac{i+0.5+i+0.25}{(i+0.5) \ ( i+0.25) } ) =  \frac{i^2 + 0.75i}{i^2 + 0.75 i + 0.125}

           i² + 0.75 i + 0.125 = 2i² + 0.75 i

           i² - 0.125 = 0

           i = √0.125

           i = 0.35355 A

with the second equation we look for R1

          R₁ = \frac{V}{i+0.5}

          R₁ = 12 /( 0.35355 +0.5)

          R₁ = 14.1 Ω

with the third equation we look for R2

          R₂ = \frac{V}{i+0.25}

          R₂ =\frac{12}{0.35355+0.25}

          R₂ =  19.9 Ω

3 0
2 years ago
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