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Sergeu [11.5K]
3 years ago
5

(40 points)

Chemistry
2 answers:
Genrish500 [490]3 years ago
6 0

Answer:

The sample will dissolve in more than 1 minute.

Explanation:

In order to answer this question, we have to consider several significant aspects:

  • temperature is directly proportional to kinetic energy, that is, the greater the temperature, the greater the kinetic energy. Since kinetic energy measures velocity of the particles, this means that the greater the temperature, the greater the velocity of the individual ions of potassium phosphate;
  • we may conclude from the first fact that the number of collisions in a given amount of time will then increase due to an increase in velocity;
  • it also follows that the greater the temperature, the faster our salt dissolves due to an increase in the number of successful collisions.

This means that at a lower temperature, the sample will dissolve in a longer period of time.

fomenos3 years ago
6 0

Answer:

(3.09)  The sample will dissolve in more than 1 minute.

Explanation:

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Answer:

300K.

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 300L

Initial temperature (T1) = 200K

Final volume (V2) = 450L

Final temperature (T2) =..?

Since the pressure is constant, the gas is obeying Charles' law.

Using the Charles' law equation, we can obtain the new temperature of the gas as follow:

V1/T1 = V2/T2

300/200 = 450/T2

Cross multiply to express in linear form

300 x T2 = 200 x 450

Divide both side by 300

T2 = (200 x 450)/ 300

T2 = 300K

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A sample of iron is put into a calorimeter (see sketch at right) that contains of water. The iron sample starts off at and the t
Mariulka [41]

Answer:

Therefore, the specific heat capacity of the iron is 0.567J/g.°C.

<em>Note: The question is incomplete. The complete question is given as follows:</em>

<em>A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm. </em>

<em> Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits</em>

Explanation:

Using the formula of heat, Q = mc∆T  

where Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)

When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water

mass of iron  = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C

∆T = 85.0 °C - 27.6 °C = 57.4 °C

mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C

∆T = 27.6°C - 23.0°C = 4.6 °C

Substituting the values above in the equation; Heat lost by Iron = Heat gained by water

59.1 g * c * 57.4 °C  = 100.0 g * 4.184 J/g.°C * 4.6 °C

c = 0.567 J/g.°C

Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.

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