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VLD [36.1K]
3 years ago
10

Alex hope in her parked car, turns the key, and slams on the gas, producing an acceleration of 4.8m/s2. If she does this for 4,4

seconds how far will she have traveled
Physics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

She has travelled 46.46 meters

Explanation:

<u>Step 1:</u> Data given

The car starts from rest so v0 = 0 m/s

Acceleration a = 4.8 m/s²

Time travelled = 4.4 seconds

<u>Step 2:</u> Calculate the distance

Since this is an acceleration we will use the formula X = 1/2 * at² +v0t + x0

with X = the total distance travelled

with x0 = the start point ( in this case it's 0)

with a = the acceleration ( in this case 4.8 m/s²)

with v0 = the initial speed ( in this case 0 m/s)

with t= the time travelled (in this case 4.4s)

X = 1/2 * 4.8 m/s² * (4.4s)² + 0*4.4s + 0

X = 1/2 * 4.8 m/s² * (4.4s)²

X = 46.46 m

She has travelled 46.46 meters

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A tiny object carrying a charge of +44 μC and a second tiny charged object are initially very far apart. If it takes 21 J of wor
STatiana [176]

Answer:

The magnitude of the second charge is \rm 1.062\times 10^{-7}\ C or \rm 0.1062\ \mu C.

Explanation:

The work done in bringing a charged particle from one point to another in the presence of some electric field is equal to the change in the electric potential energy of the charge in moving from one point to another.

The electric potential energy of some charge q_o at a point in the electric field of another charge q is given by the product of the amount of charge q_o and electric potential at that point due to the charge q.

U = q_o\ V.

The electric potential at that point is given by

V = \dfrac{kq}{r}.

where k is the Coulomb's constant.

Therefore,

U=q_o\ \dfrac{kq}{r}.

Now, We have given two charges q_1 = +44\ \mu C = +44\times 10^{-6}\ C and q_2, whose value is to be found.

When the two charges are infinitely dar apart, the electric potential energy of the system is given by

U_i = \dfrac{kq_1q_2}{\infty}=0.

When the coordinates of position of the two charges are

(x_1,\ y_1) = (1.00\ mm,\ 1.00\ mm).\\(x_2,\ y_2) = (1.00\ mm,\ 3.00\ mm).

The distance between the two charges is given by

r=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(1.00-1.00)^2+(3.00-1.00)^2}=2.00\ mm = 2.00\times 10^{-3}\ m.

The electric potential energy of the charges in this configuration is given by

U_f = \dfrac{kq_1q_2}{r}\\=\dfrac{(8.99\times 10^9)\times (+44\times 10^{-6})\times q_2}{2.00\times 10^{-3}}\\=1.9778\times 10^8\times q_2.

The change in the electric potential energy of the system is equal to the work done to bring the system from inifinitely far apart position to given configuration.

Therefore,

W = U_f-U_i\\21=(1.9778\times 10^8\times q_2)-0\\\Rightarrow q_2 = \dfrac{21}{1.9778\times 10^8}\\=1.062\times 10^{-7}\ C\\=0.1062\times 10^{-6}\ C\\=0.1062\ \mu C.

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3 years ago
Which is true of a mechanical wave?
timurjin [86]
A) It must have a medium.
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3 years ago
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When planning an experiment, a scientist must first choose a question to investigate. In an experiment, Renata changes the relea
dangina [55]

Answer:

The correct option is D

Explanation:

In the course of the experiment, two key phrases/variables defined the experiment done,

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ii) the distance the ball travels from the ramp before falling to the ground (dependent variable)

The only option that contains and relates this two variables as carried out during the course of the experiment is option D.

6 0
3 years ago
Una grúa efectúa un trabajo de 45000 joules en 0.1
Hunter-Best [27]

Answer:

<em>P = 7.5 KW</em>

<em>P = 7500 W</em>

Explanation:

<u>Potencia Mecánica</u>

Es una medida del trabajo realizado por un agente por unidad de tiempo.

Siendo W el trabajo mecánico y t el tiempo necesario para realizarlo, entonces la potencia viene dada por:

\displaystyle P=\frac{W}{t}

La unidad SI de la potencia es el vatio (W). Otra unidad muy común es el kilovatio (KW). 1 KW = 1000 W.

La grúa realiza un trabajo W=45000 Joules en un tiempo de t=0.1 minutos.

Para calcular la potencia en vatios, es necesario llevar el tiempo a segundos:

t = 0.1 min *60 = 6 segundos.

La potencia se calculará ahora:

\displaystyle P=\frac{45000}{6}

P = 7500 W

En kilovatios:

P = 7500 / 1000 = 7.5 KW

P = 7.5 KW

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Which of these is not an official SI unit of measure?
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I believe its b. degree Celsius <span />
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