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Likurg_2 [28]
3 years ago
13

The internal pressure on a bottle of soda is 5550 torr. the bottle cap is designed to withstand a pressure of 7.2 atm. (a) calcu

late the pressure in atm
Physics
2 answers:
Mademuasel [1]3 years ago
6 0

This is a conversion problem. 760 Torr is equal to 1 atmosphere. so we can can solve now. 5,550torr*(1atmosphere/760torr)=7.3atmospheres. since the two torrs cancel out with cross multiplication we are left in atmosphere units.

Kryger [21]3 years ago
4 0

Answer:

The internal pressure on the bottle of soda is 7.303atm

Explanation:

We know that ''torr.'' is actually Torricelli a pressure unit. In order to find this pressure in ''atm'' (which is another pressure unit) we need to know the conversion factor.

The conversion factor is the following :

1atm=760torr.

If we use the conversion factor to find the pressure in atm :

(5550torr.).(\frac{1atm}{760torr.})=7.303atm

We found out that 5550torr. are equal to 7.303atm

You can find the conversion factor on any units table.

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A vector R is resolved into its components, Rx and Ry. If the ratio of is 2, what is the angle that the resultant makes with the
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The angle is 26.56 degrees
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What are some examples of irreversible processes in nature?
castortr0y [4]

Answer:

Burning. When you burn something, it turns into ash you can't make that thing turn into what it was before.

8 0
3 years ago
Ann (mass 50 kg) is standing at the left end of a 15-m-long, 500 kg cart that has frictionless wheels and rolls on a frictionles
ivanzaharov [21]

Answer:

13.5 m

Explanation:

M = Mass of cart = 500 kg

m = Ann's mass = 50 kg

v_m = Velocity of Ann relative to cart = 5 m/s

v_M = Velocity of Cart relative to Ann

As the linear momentum of the system is conserved

Mv_M+mv_m=0\\\Rightarrow v_M=-\frac{mv_m}{M}\\\Rightarrow v_M=-\frac{50\times 5}{500}\\\Rightarrow v_M=-0.5\ m/s

Time taken to reach the right end by Ann

Time=\frac{Distance}{Speed}\\\Rightarrow Time=\frac{15}{5}=3\ s

Distance the cart will move in the 3 seconds

Distance=Speed\times Time\\\Rightarrow Distance=-0.5\times 3=-1.5\ m

The negative sign indicates opposite direction

Movement of Ann will be the sum of the distances

15+(-1.5)=13.5\ m

The net movement of Ann is 13.5 m

5 0
3 years ago
Any help guys? I am stuck on two problems.
Juli2301 [7.4K]

Ax=A*Cos56

   = 20*(0.559)

   = 11.18 N

8 0
3 years ago
A bodybuilder deadlifts a 215 kg weight to a height of 0.90 m above the ground. If he deadlifts this weight 10 times in a span o
wariber [46]

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

<h3>What is power?</h3>

In physics, power (P) is the work (W) done over a period of time.

  • Step 1. Calculate the work done by the bodybuilder each time.

The bodybuilder lifts a 215 kg (m) weight to a height of 0.90 m (h). Being the gravity (g) of 9.81 m/s², we can calculate the work done in each lift using the following expression.

W = m × g × h = 215 kg × 9.81 m/s² × 0.90 m = 1.9 × 10³ N

  • Step 2. Calculate the work done by the bodybuilder over 10 times.

W = 10 × 1.9 × 10³ N = 1.9 × 10⁴ N

  • Step 3. Calculate the power exerted by the bodybuilder.

The bodybuilder does a work of 1.9 × 10⁴ N in a 45-s span.

P = 1.9 × 10⁴ N/45 s = 421 W

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

Learn more about power here: brainly.com/question/911620

#SPJ1

4 0
2 years ago
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