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3 years ago

A baseball is thrown straight out from a mound at 40 m/s and lands 21m away. how tall is the mound

Physics

1 answer:

morpeh [17]3 years ago

7 0

Answer:

1.35 m

Explanation:

First, find the time it takes to land. Given in the x direction:

Δx = 21 m

v₀ = 40 m/s

a = 0 m/s²

Find: t

Δx = v₀ t + ½ at²

(21 m) = (40 m/s) t + ½ (0 m/s²) t²

t = 0.525 s

Next, find the height. Given in the y direction:

v₀ = 0 m/s

a = 9.8 m/s²

t = 0.525 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (0.525 s) + ½ (9.8 m/s²) (0.525 s)²

Δy = 1.35 m

Round as needed.

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stealth61 [152]

Answer:

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Explanation:

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$R=\frac{\rho L}{A}$

$\rho$ is the material's resistance, L is the legth and A is the cross-sectional area.

For the first and second coils, we have:

$R_1=\frac{\rho L}{A_1}\\R_2=\frac{\rho L}{A_2}\\\rho L=R_1A_1\\\rho L=R_2A_2\\R_1A_1=R_2A_2\\\frac{R_2}{R_1}=\frac{A_1}{A_2}$

For the third and fourth coils, we have:

$R_3=\frac{\rho L'}{A_3}\\R_4=\frac{\rho L'}{A_4}\\\rho L'=R_3A_3\\\rho L'=R_4A_4\\R_3A_3=R_4A_4\\\frac{R_4}{R_3}=\frac{A_3}{A_4}$

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3 years ago

if the Horse and Rider have a combined mass of 572 kg what force would be required to accelerate them 5 kph per second

Vlad [161]

Answer:

Force required to accelerate = 794.44 N

Explanation:

Force required = Mass of horse x Acceleration of horse

Mass of horse and rider, m= 572 kg

Acceleration of horse and rider, a = 5 kph per second

$=\frac{5*1000}{60*60} =1.39 m/s^2$

Force required = ma

= 572 x 1.39 = 794.44 N

Force required to accelerate = 794.44 N

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Answer:

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