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shtirl [24]
3 years ago
11

A chain 27 feet long whose weight is 95 pounds is hanging over the edge of a tall building and does not touch the ground. How mu

ch work is required to lift the entire chain to the top of the building?
Mathematics
1 answer:
bazaltina [42]3 years ago
6 0

Answer:

Work done = 2,565 lb-ft

Step-by-step explanation:

The density of the chain in lb/ft  is equal to

\frac{95}{27} lb/ft

Total Work done is equal to the summation of  work done up to the top of building.

We will use integration for this evaluation.

The mathematical relation is as follows

\int\limits^{40}_0 {X} \, pdx

where "p" is the density

Substituting the given values, we get

\frac{95}{27} \int\limits^{27}_0 {X} \, dx\\\frac{95}{27}  X^2\int\limits^{27}_0\\ \frac{95}{27}  {27^2 - 0^2}\\\frac{95}{27}  * 27 * 27\\95* 27\\= 2,565

Work done = 2,565 lb-ft

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