Distance for which the bike is ridden = 30 km
Speed at which the bike is driven = 0.75 km/minute
Let us assume the number of minutes taken to travel the distance of 30 km = x
Now we already know the formula of speed can be written as
Speed = Distance traveled/ Time taken
0.75 = 30/x
0.75x = 30
x = 30/0.75
= 40 minutes
So the time taken for riding a distance of 30 km will be 40 minutes. I hope this procedure is simple enough for you to understand.
Answer:
The answer should be light or other electromagnetic radiation
Explanation:
Such as x-rays or other things like that.
<em>-Hope This Helps!</em>
<em>-Justin:)</em>
Answer:
The formula is a = F m so in this case a = 5 10 = 0.5 m s 2
Explanation:
Both, there are two different types of molecules to distinguish that
Answer:
a) v = 19,149.6 m/s
b) f = 95%
c) t = 346.5min
Explanation:
First put all values in metric units:
![15.8 min*\frac{60s}{1min}=948s](https://tex.z-dn.net/?f=15.8%20min%2A%5Cfrac%7B60s%7D%7B1min%7D%3D948s)
The equation of motion you need is:
where
is the final velocity, a is acceleration and t is time in hours.
Since the spaceship starts from 0 velocity:
![v_f = a*t = 20.2*948 = 19,149.6 m/s](https://tex.z-dn.net/?f=v_f%20%3D%20a%2At%20%3D%2020.2%2A948%20%3D%2019%2C149.6%20m%2Fs)
Next, you need to calculate the distances traveled on each interval, considering that both starting and final intervals travel the same distance because the acceleration and time are equal. For this part you need the next motion equation:
![x=\frac{v_0+v_f}{2}t](https://tex.z-dn.net/?f=x%3D%5Cfrac%7Bv_0%2Bv_f%7D%7B2%7Dt)
solving for first and last interval:
Since the spaceship starts and finish with 0 velocity:
![x=\frac{v}{2}t=\frac{19,149.6}{2}948=9,076,910.4m=9,076.9104km](https://tex.z-dn.net/?f=x%3D%5Cfrac%7Bv%7D%7B2%7Dt%3D%5Cfrac%7B19%2C149.6%7D%7B2%7D948%3D9%2C076%2C910.4m%3D9%2C076.9104km)
Then the ship traveled
at constant speed, which means that it traveled:
![f_{constant_speed} =\frac{ x_{constant_speed}}{x_total} =\frac{361,846.1792}{380,000} =0.95](https://tex.z-dn.net/?f=f_%7Bconstant_speed%7D%20%3D%5Cfrac%7B%20x_%7Bconstant_speed%7D%7D%7Bx_total%7D%20%3D%5Cfrac%7B361%2C846.1792%7D%7B380%2C000%7D%20%3D0.95)
Which in percentage is 95% of the trip.
to calculate total time you need to calculate the time used during constant speed:
![t = \frac{361,846,179.2}{19,149.6} = 18,895.75s = 314min](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B361%2C846%2C179.2%7D%7B19%2C149.6%7D%20%3D%2018%2C895.75s%20%3D%20314min)
That added to the other interval times:
![t_{total} = t_1+t_2+t_3=15.8+314.93+15.8=346.5min](https://tex.z-dn.net/?f=t_%7Btotal%7D%20%3D%20t_1%2Bt_2%2Bt_3%3D15.8%2B314.93%2B15.8%3D346.5min)