Answer:
2N2H2SO4
Explanation:
this is your answer calculate
Answer:
n=17.85 moles
Explanation:
Given mass is, m = 1.5 kg = 1500 g
The molar mass of sodium bicarbonate is, M = 84.007 g/mol
We need to find the no of moles in 1.5 kg of Sodium bicarbonate . We know that, no of moles is equal to given mass divided by molar mass.
<h2>
So, there are 17.85 moles in 1.5 kg of Sodium bicarbonate.</h2>
Answer:
3.91 L
Explanation:
Using the ideal gas law equation as follows:
PV = nRT
Where:
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
Based on the information given in this question,
P = 5.23 atm
V= ?
n = 0.831 mol
T = 27°C = 27 + 273 = 300K
Using PV = nRT
V = nRT/P
V = (0.831 × 0.0821 × 300) ÷ 5.23
V = 20.47 ÷ 5.23
V = 3.91 L
Answer:
frequency it the measure of the wave length. The measure of the peaks and troughs is how you measure the frequency. the distance between these is the wave length.
