Answer:
The water must flow with the velocity of 141.4m/s
Explanation:
The kinetic energy is energy due to the motion of a body
In this Case the kinetic energy of the turbine is given as
KE=1/2mv²
Where KE= kinetic energy
m= mass of water
v= velocity of the water
Data given
KE=10000j
m=1000g------kg =1000/1000= 1kg
v=?
Substituting our data into the expression we have
10,000=1/2(1*v²)
10,000=v²/2
Solving for v we have
v²=20,000
v=√20,000
v=141.4m/s
Answer:
A general solution is 
and a particualr case is mgh, it is just to distance around the radius Earth.
Explanation:
We can use a general equation of the potential energy to understand the particular and general case:
The potential energy is defined as 
, we know that the gravitational force is 
, so we could find the potential energy taking the integral of F.
(1)
We can find the particular case, just finding the gravitational potential energy difference:
. Here Uf is the potential evaluated in r+Δh and Ui is the potential evaluated in r.
Using (1) we can calculate ΔU.
Simplifying and combining terms we have a simplified expression.
(2)
Let's call 
. It is the acceleration due to gravity on the Earth's surface, if r is the radius of Earth and M is the mass of the Earth and we can write (2) as ΔU=mgh, but if we have distance grader than r we should use (2), otherwise, we could get incorrect values of potential energy.
I hope i hleps you!
Answer:
10000N
Explanation:
Given parameters:
Mass of the car = 1000kg
Acceleration = 3m/s²
g = 10m/s²
Unknown:
Weight of the car = ?
Solution:
To solve this problem we must understand that weight is the vertical gravitational force that acts on a body.
Weight = mass x acceleration due to gravity
So;
Weight = 1000 x 10 = 10000N
Answer:
The color of the light is determined by the frequency of the light wave. Red, is lowest, frequency and violet is the highest.
Answer:
the energy when it reaches the ground is equal to the energy when the spring is compressed.
Explanation:
For this comparison let's use the conservation of energy theorem.
Starting point. Compressed spring
Em₀ = K_e = ½ k x²
Final point. When the box hits the ground
Em_f = K = ½ m v²
since friction is zero, energy is conserved
Em₀ = Em_f
1 / 2k x² = ½ m v²
v = 
x
Therefore, the energy when it reaches the ground is equal to the energy when the spring is compressed.
