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Reptile [31]
4 years ago
13

What homemade things could I use for wheels on a small balloon powered car?

Physics
2 answers:
Fantom [35]4 years ago
8 0

You can use mostly anything as long as it is circular. Depending on how big it is, you could use sturdy paper plates and use a stick/rod and tape to hold it together, or you could use bottle caps if the car you are trying to make is really small.

Brilliant_brown [7]4 years ago
8 0
CD disks can be used too.
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What is the radius of the event horizon of a 10 solar mass black hole?
deff fn [24]

Answer:

The number take for the "radius" is normally taken to be the radius from the center to the event horizon, since nothing inside that can be observed, and since it is a point of no return. This radius is directly proportional to the mass of the black hole. From the Wikipedia article on event horizon: "For the mass of the Sun this radius is approximately 3 kilometers and for the Earth it is about 9 millimeters. In practice, however, neither the Earth nor the Sun has the necessary mass and therefore the necessary gravitational force, to overcome electron and neutron degeneracy pressure." The last sentence means that it is unlikely for the Sun to become a black hole, since it has too little mass to become one.

Explanation:

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3 years ago
What is the magnitude of the force a 25 mC charge exerts on a +2.5 mC charge 16 cm away?
kakasveta [241]
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5 0
3 years ago
The bass tones rattling the windows of the car next to you at a red light are at a __________.
Andrew [12]
... low frequency and high amplitude.
4 0
3 years ago
A 3 kg object is moving along a horizontal surface. The kinetic energy of the object is increasing at a constant rate of 6 J/m;
Whitepunk [10]

To solve this problem we will apply the concepts of energy conservation and Newton's second law that defines force as the product of the object's mass with its acceleration. Additionally we will apply concepts related to the kinematics equations of linear motion.

For conservation of energy we have that work is equal to kinetic energy therefore,

W = KE

Fd = \frac{1}{2} mv^2

Here,

F = Force

d = Displacement

m = Mass

v= Velocity

At the same time we have the relation of

F = \frac{W}{d}

Therefore the value of the force can be interpreted as the rate of increase in energy per unit of distance, which makes it equivalent to

F = \frac{W}{d} = 6J/m

Applying Newton's Second Law

F = ma

6J/m = (3kg)a

a = 2m/s^2

In 4 seconds final velocity of the object becomes

v = at

v= 2*4

v= 8m/s

Then the work done is equal to,

W = KE

W = \frac{1}{2} mv^2

W = \frac{1}{2} (3)(82)

W = 96J

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W = F*d

d = \frac{W}{F}

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7 0
4 years ago
9. Carlos jumps out of a hovering helicopter. After he opens his parachute, his acceleration due to gravity decreases
nata0808 [166]

Answer:

A The force of air resistance becomes equal in magnitude to his weight.

Explanation:

When Carlos jumped out of the helicopter, he fell with a downward force which is proportional to his weight.

His weight is the product of his mass and acceleration due to gravity.

When the parachute is deployed, air resistance between the air molecules and the surface area of the parachute generates a drag force, which acts upwards.

If the drag forces exceeds his weight, then his net force will be directed upwards.

If his weight exceeds the drag forces, then the net force on his body will be downwards.

In the case that his drag force, and his weight are equal, there will be a zero net force on him, and he will experience no acceleration.

So, if after he opens his parachute, his acceleration due to gravity decreases  to zero, then we can say that this is because  the force of air resistance (drag) becomes equal in magnitude to his weight.

5 0
4 years ago
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