Answer:
The mass of oxygen needed to be pumped in the aquarium is 10 g
Explanation:
Here the value of the degree of solubility of oxygen in water is sought
The solubility of oxygen in fresh water is approximately 1.22 × 10⁻³ mol·dm⁻³ which is equivalent to approximately 40 mg/L
The volume of water the aquarium holds = 250 L
The mass of oxygen required = The solubility of oxygen in water × (The volume of water in the aquarium)
Therefore, the mass of oxygen needed to be pumped in the aquarium = 40 mg/L × 250 L = 10,000 mg
1,000 mg = 1 g
∴ 10,000 mg = 10 g
The mass of oxygen needed to be pumped in the aquarium = 10,000 mg = 10 g.
The krypton-83 isotopes below is formed when rubidium-83 undergoes electron capture.
What is isotopes?
isotopes are defined as atoms with a constant number of protons but a variable number of neutrons. Despite having different masses and hence having different physical qualities, they have nearly identical chemical properties.
What is stable nuclide?
Since stable nuclides are not radioactive, they do not spontaneously decay into radioactive elements as happens with radionuclides. They are commonly referred to as stable isotopes when such nuclides are discussed in connection to particular elements.
The electron capture process will turn rubidium-83 into krypton-83. When a proton in the nucleus catches an inner electron and creates a neutron, this process is known as electron capture.
Therefore, krypton-83 isotopes below is formed when rubidium-83 undergoes electron capture.
Learn more about isotopes from the given link.
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3.4 mole Cu (6.022 X 10^23/1mol Cu ) = 2.047 X 10^23 atoms of copper.<span>
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