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natima [27]
4 years ago
7

The equilibrium in a saturated solution of Ca(OH)2 is represented above. In an experiment, a student places 5.0g of Ca(OH)2(s) i

nto 100.0mL of distilled water and stirs the mixture. How would the results be affected if the student repeats the experiment but this time places 5.0g of Ca(OH)2(s) into 100.0mL of 0.0010MNaOH(aq) instead of distilled
Chemistry
1 answer:
Fofino [41]4 years ago
8 0

Answer:

The answer is b) Less solid will disolve, because the larger value of [OH]- will cause the equilibrium position to lie farther to the left.

Explanation:

According to the reactions:

Ca(OH)2 = Ca2+ + 2OH-

NaOH = Na+ + OH-

The balance in the less solid solution will shift to the left, to keep the sodium hydroxide concentration in balance. This is produced by the common ionic effect in both reactions due to hydroxide (OH-) ions that are created due to sodium hydroxide NaOH, therefore, the solubility of calcium hydroxide Ca(OH)2 will be reduced. In conclusion we can say that the balance in the reaction will be more to the left.

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Weak; a lot of potential energy.

Explanation:

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During a class demonstration the potassium exploded. Suggest what might have caused this to happen
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A chemical reaction in a lab experiment actually produces 1.23mol of BeBr2. The theoretical yield is 220g. To two decimal places
Mashutka [201]

Answer:

Percent yield = 94.62%

Explanation:

Given data:

Actual yield of BeBr₂ = 1.23 mol

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Solution:

Theoretical yield in moles:

Number of moles = mass/molar mass

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5 0
3 years ago
According to the following reaction, how many grams of hydrogen peroxide (H2O2) are needed to form 32.0 grams of oxygen gas?
Nesterboy [21]

Answer:

The answer to your question is 34 g of H₂O₂    

Explanation:

Data

mass of H₂O₂ = ?

mass of O₂ = 32 g

Process

1.- Write the balanced chemical reaction

                   H₂O₂  ⇒   H₂  +  O₂

2.- Calculate the molar mass of H₂O₂ and O₂

Molar mass H₂O₂ = (1 x 2) + (16 x 2) = 34 g

Molar mass of O₂ = 2 x 16 = 32 g

3.- Use proportions to calculate the mass of O₂

                    34g of H₂O₂ -------------- 32g of O₂

                     x                   -------------- 32g of O₂

                          x = (32 x 34) / 32

                          x = 34 g of H₂O₂                                

5 0
3 years ago
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