Answer:
No. Of Moles of zinc = m/Ar
= 13/ 65.38 = 0.198 moles
From balanced equation, Mole ration between CuSO4 and Zn is 1 : 1
So only 0.198 moles of CuSO4 reacts, it is in excess
Mass = no of Moles X Mr
Mass = 0.198 X 159.5 = 31.59 grams
Volume = mass m denisty
Volume j 31.59 / 3.6 = 8.78 ml
Explanation:
i think this wrong
Answer:
[The rate differential results from induced fit on the enzyme upon binding of glucose. This conformational change excludes water from gaining access to the -phosphate group on ATP, and brings the same group close to the OH group on carbon 6 of glucose]
Explanation:
Answer:
See explanation
Explanation:
The oxides or hydrides are formed by exchange of valency between the two atoms involved. The group of the atom bonded to oxygen or hydrogen in the binary compound can be deduced by considering the subscript attached to the oxygen or hydrogen atom.
Now let us take the journey;
R2O3- refers to an oxide of a group 13 element, eg Al2O3
R2O - refers to an oxide of group a group 1 element e.gNa2O
RO2 - refers to an oxide of a group 14, 15 or 16 element such as CO2, NO2 or SO2
RH2 - refers to the hydride of a group 12 element Eg CaH2
R2O7 - refers to an oxide of a group 17 element E.g Cl2O7
RH3- refers to a hydride of a group 13 element E.g AlH3
Answer:
We need to add 900 mL of water.
Explanation:
To know the amount of water to add first we need to calculate the concentration of KOH when the pH is 12 and when is 11:
When pH = 12 (initial):
When pH = 11 (final):
Now, by using the following equation we can find the volume of the solution to achieve a pH = 11:
Finally, to bring 100 mL of the initial solution to 1000 mL we need to add the following amount of water:
Therefore, we need to add 900 mL of water.
I hope it helps you!