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Burka [1]
3 years ago
15

Apply Newton's first law to each of the following situations. In which situations can you conclude that the object is undergoing

a net interaction with one or more other objects? A car travels at constant speed around a circular race track.
Physics
1 answer:
Vsevolod [243]3 years ago
8 0

You only list one situation, are there any more?

You might be interested in
A uniform 40-N board supports two children weighing 500 N and 350 N. If the support is at the center of the board and the 500-N
serg [7]

Answer:

b= 2.14 m

Explanation:

Given that

Weight of the board ,wt = 40 N

Wight of the first children , wt₁=500 N

Weight of the second children ,wt₂ = 350 N

The distance of the 500 N child from center ,a= 1.5 m

lets take distance of the 350 N child from center = b m

Now by taking the moment about the center of the board

We know that moment = Force x Perpendicular distance from the force

wt₁ x a = wt₂ x b

500 x 1.5 = 350 x b

b= 2.14 m

Therefore the distance of the 350 N weight child from the center is 2.14 m.

5 0
2 years ago
A car traveling 35 km/hr accelerates to a speed of 45 km/hr in .25 hr. What is its acceleration
ahrayia [7]

Answer:

a=40Km/hr^2

Explanation:

6 0
2 years ago
A toaster is plugged into a 132 volt household circuit it draws the amps of current If you use a toaster 2 hours a week how much
Ne4ueva [31]
There is a missing data in the text of the problem: the current drawn is 0.5 A (found on internet)

Solution:
The power used by the toaster is the product between the voltage V and the current I:
P=VI=(132 V)(0.5 A)=66 W=0.066 kW

The toaster is used for a time of 2 hours: t=2h, therefore the energy used is equal to
E=Pt =(0.066 kW)(2 h)=0.132 kWh
8 0
2 years ago
An elderly sailor is shipwrecked on a desert island but manages to save his eyeglasses. The lens for one eye has a power of 1.16
igomit [66]

Answer:

m = 8

Explanation:

A telescope is a device that allows us to see objects that were very far from us, it is built by the combination of two lenses, the one with the lowest focal length near the eye and that is the one or the one with the greatest focal length, the most eye-flounder . The magnification of the telescope is

            m = - f₀ / f_{e}

Where f₀ is the focal length of the lens and f_{e} is the false distance of the eyepiece.

It is this problem that gives us the diopter of each lens, these are related to the focal length in meters

           D = 1 / f

Let's find the focal length

       f₁ = 1 / D₁

       f₁ = 1 / 1.16

       f₁ = 0.862 m

     

        f₂ = 1 / 9.37

        f₂ = 0.1067 m

Therefore, the lens with f₂ is the eyepiece and the slow one with the  

distance focal  f₁ is the objective.

Let's calculate

       m = - f₂ / f₁

      m = - 0.862 / 0.1067

      m = 8

8 0
2 years ago
How can understanding velocity help to prevent a mid-air collision
dsp73

Answer:

To maintain enough time to prevent a collision, a system operating in air traffic where aircraft speed does not

fall below 100 km/h (most medium-sized UAVs and GA aircraft) will need to be able to detect obstacles which

subtend an arc-width of as small as 0.125 mra

7 0
2 years ago
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