First, we need to find the atomic mass of

.
According to the periodic table:
The atomic mass of Carbon = C = 12.01
The atomic mass of Hydrogen = H = 1.008
The atomic mass of Oxygen = O = 16
As there are 6 Carbons, 12 Hydrogens and 6 Oxygens, therefore:
The
molar mass of

= 6 * 12.01 + 12 * 1.008 + 6 * 16
The
molar mass of

= 180.156
grams/moleNow that we have the molar mass of

, we can find the grams of glucose by using:
mass(of glucose in grams) = moles(of glucose given in moles) * molar mass(in grams/mole)
Therefore,
mass(of glucose in grams) = 2.47 * 180.156
mass(of glucose in grams = 444.99 grams
Ans: Mass of glucose in grams in 2.47 moles =
444.99 grams
-i
Answer is: there are two compounds with molecular formula C₂H₆O, one alcohol and one ethar.
Alcohol with molecular formula C₂H₆O is ethanol or ethyl alcohol (C₂H₅OH).
Ethanol is a volatile, flammable, colorless liquid with characteristic odor.
Ether with molecular formula C₂H₆O is dimethyl ether (CH₃OCH₃).
Dimethyl ether is a colorless gas.
The principle that requires that a chemical equation be balanced would be the law of definite proportions. It <span>states that a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation. Hope this answers the question.</span>
Answer:
1) Ca: [Ar]4s²
2) Pm: [Xe]6s²4f⁵
Explanation:
1) Ca:
Its atomic number is 20. So it has 20 protons and 20 electrons.
Since it is in the row (period) 4 the noble gas before it is Ar, and the electron configuration is that of Argon whose atomic number is 18.
So, you have two more electrons (20 - 18 = 2) to distribute.
Those two electrons go the the orbital 4s.
Finally, the electron configuration is [Ar] 4s².
2) Pm
The atomic number of Pm is 61, so it has 61 protons and 61 electrons.
Pm is in the row (period) 6. So, the noble gas before Pm is Xe.
The atomic number of Xe is 54.
Therefore, you have to distribute 61 - 54 = 7 electrons on the orbitals 6s and 4f.
The resultant distribution for Pm is: [Xe]6s² 4f⁵.
Your question looks a bit incomplete as you have the same contents in options a) and d). According to your list, I can't see the correct answer, but I can give you one.The difference between the potential energy of the products of the potential energy of the reactants is equal to the enthalpy of the reaction.