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3 years ago

13

An object, with a final position of x = 100.1 meters, initially started at x = -12.13 meters. What was its displacement? (Unit =

m)

1 answer:

nikklg [1K]3 years ago

8 0

Answer:

112.23 m

Explanation:

Displacement is the final position minus the initial position.

Δx = x − x₀

Δx = 100.1 m − (-12.13 m)

Δx = 112.23 m

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A 3.0-kg block starts at rest at the top of a 37° incline, which is 5.0 m long. Its speed when it reaches the bottom is 2.0 m/s.

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Answer: $f_{r}$ = 16.49N

Explanation: The object is placed on an inclined plane at an angle of 37° thus making it weight have two component,

$W_{x}$ = horizontal component of the weight = mgsinФ

$W_{y}$ = vertical component of weight = mgcosФ

Due to the way the object is positioned, the horizontal component of force will accelerate the object thus acting as an applied force.

by using newton's law of motion, we have that

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we need to first get the acceleration before the frictional force which is gotten by using the equation below

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17.9633 - $f_{r}$ = 1.2

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