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castortr0y [4]
2 years ago
5

If a construction worker drops a wrench from the top of a building 450 feet high the wrench will be s(t) = −16t 2 + 450 feet abo

ve the ground after t seconds. Determine the velocity of the wrench 2 seconds after it was was dropped. Answer in units of ft/sec.
Physics
1 answer:
creativ13 [48]2 years ago
6 0

Answer:

-64ft/s

Explanation:

Given:

s(t)=-16t^2+450

Unknown:

\frac{ds}{dt}=v(t)=-32t

For t = 2:

v(2)=-32\times 2=-64

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From the data table we extract that there were two objects (X and Y) that underwent an inelastic collision, moving together after the collision as a new object with mass equal the addition of the two original masses, and a new velocity which is the unknown in the problem).

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Object's X initial velocity was positive (let's imagine it on a horizontal axis pointing to the right) of 10 m/s. Object Y had a negative velocity (imagine it as pointing to the left on the horizontal axis) of -6 m/s.

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Since in the collision there is conservation of the total momentum, this initial quantity should equal the quantity for the final mometum of the stack together system (that has a total mass of 400 kg):

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