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MissTica
4 years ago
14

A 200 kg object is going 4 m/s. Find it’s kinetic energy

Physics
1 answer:
Karo-lina-s [1.5K]4 years ago
3 0

1/2mv^2

1/2(200)(4)^2

100(16)

1600 J

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All of the following statemants about the earths atmosphere are true except:
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8 0
3 years ago
A machine that operates a ride at the fair requires 2500 J to lift a 294 N child 5.0 m. What is the efficiency of this machine?
NeX [460]

Answer:

η = 58.8%

Explanation:

Work is defined as the force applied by the distance traveled by the body.

W =F*d

where:

W = work [J] (units of joules)

F = force = 294 [N]

d = distance = 5 [m]

W = 294*5\\W = 1470 [J]\\

Efficiency is defined as the energy required to perform an activity in relation to the energy actually added to perform some activity. This can be better understood by means of the following equation.

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3 years ago
Winds are deflected to the (right/left) ___ as they move into a low pressure area in the Northern Hemisphere.
SashulF [63]

Winds are deflected to the right as they move into a low pressure area in the Northern Hemisphere.

<u>Explanation:</u>

Winds decide the motion of ocean currents which forms the surface waves in the Earth's atmosphere to maintain the pressure region. The motion of ocean currents is based on Coriolis force which states the direction of motion of an object in a rotating system.

In the case of Earth, the Coriolis force has an effect on the ocean currents which are deflected from maximum to minimum pressure region in a curved path. So the winds formed by the ocean currents will generally get deflected at the right as they move into a low pressure area at the Northern Hemisphere from the high pressure region.

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3 years ago
What is the temperature of a sample of gas when the average translational kinetic energy of a molecule in the sample is 8.37 × 1
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Answer:

404K

Explanation:

Data given, Kinetic Energy.K.E=8.37*10^-21J

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This relationship can be expressed as

K.E=\frac{3}{2}KT

where K is a constant of value 1.38*10^-23

Hence if we substitute the values, we arrive at

T=\frac{2/3(8.37*10^{-21})}{1.38*10^-23}\\ T=404K

converting to degree we have 131^{0}C

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3 years ago
Which of the following equations can be used to directly calculate an object's impulse?
Iteru [2.4K]
I believe the answer is B
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