Answer:
The higher the spring constant, the greater the elastic potential energy.
Answer:
C) must be such as to follow the magnetic field lines.
Explanation:
Ampere's circuital law helps us to calculate magnetic field due to a current carrying conductor. Magnetic field due to a current forms closed loop around the current . If a net current of value I creates a magnetic field B around it , the line integral of magnetic field around a closed path becomes equal to μ₀ times the net current . It is Ampere's circuital law . There may be more than one current passing through the area enclosed by closed curve . In that case we will take net current by adding or subtracting them according to their direction.
It is expressed as follows
∫ B.dl = μ₀ I . Here integration is carried over closed path . It may not be circular in shape. The limit of this integration must follow magnetic field lines.
the term ∫ B.dl is called line integral of magnetic field.
Answer:
The heating of saturated solutions lead to the increase in their solubility. The kinetic energy of the liquid molecules increases on increasing the temperature due to which they move apart from each other creating more space for the solute molecules to dissolve thereby increasing the solubility.
Answer:
a. 2N
b. 12N
c. 20N
Explanation:
Dtaa given,
Weight of rock in air=10N
weight of rock in water =8N
a. When the rock is suspend in water, it will displace some water from thr container since Buoyant force is the acts upward and equals in magnitude to the volume of water displays,
The buoyant force is calculated as 10N-8N=2N
b. The scale reading will be the sum of the buoyant force and the weight of the container
scale reading =10N+2N=12N
c. When the rock rest at the bottom of the container, the weight of the rock(10N) is acting downward and the weight of the container also is acting downward. Hence the sum of the two weight gives the reading on the scale
scale reading=10N+10N=20N
Given:
Shaft Power, P = 7.46 kW = 7460 W
Speed, N = 1200 rpm
Shearing stress of shaft, 
= 30 MPa
Shearing stress of key, 
= 240 MPa
width of key, w = 
d is shaft diameter
Solution:
Torque, T = 
where,
= 59.365 N-m
Now,
d = 0.0216 m
Now,
w = = 
= 5.4 mm
Now, for shear stress in key
= 
we know that
T = 
= F. 
⇒ = 
⇒ 
= 
length of the rectangular key, l = 4.078 mm
