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ser-zykov [4K]
3 years ago
12

Compare convection currents in the ocean with convection currents in the atmosphere. Use complete sentences and give at least tw

o supporting details.
(3-4 Complete sentences)
Physics
2 answers:
ioda3 years ago
8 0

Answer: In ocean, the less denser warm water due to the heat from the sun, rises up to the ocean surface and tends to move towards higher latitudinal areas. The wind generates the ocean currents and it slowly loses heat and becomes cold and denser as it approaches the polar region and then it sinks down, moves back towards the equatorial region. This constant motion of these water current in the ocean is known as the convection current.

      In the atmosphere, similar mechanism occurs. the air gets warm due to the heating of the sun and rises up to the atmosphere and as it rises up, it slowly becomes dense and again at one point it falls back because of its higher density. This continuous motion of air represents the convection current within the atmosphere.

This two phenomenon is the same as the convection that occurs at the earth's mantle, in which the hot molten magma because of its lower density rises up and gets cooled when it reaches the upper part, becoming dense again falls back.

KIM [24]3 years ago
4 0
In this way, heat inside Earth moves toward the cooler crust. This movement of rock is a COnvection Current<span>. </span>Convection Currents<span> in the mantle cause the movement of tectonic plates. Figure 4 </span>Convection currents in the atmosphere<span> form when cold </span>air<span>sinks and forces warm </span>air<span> away from Earth's surface.</span>
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Below is a circuit schematic of sources and resistors (Figure 3). VS = 10V , R1 = 100Ω, R2 = 50Ω, R3 = 25Ω, IS = 2A. Calculate t
lorasvet [3.4K]

Answer:

V_3\approx 4.28\,\,V

I_1=0.0572\,\,amps

I_3\approx 0.171\,\,amps

Explanation:

Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.

So we first find the equivalent resistance for the two resistors in parallel:

\frac{1}{Re}= \frac{1}{R1}+\frac{1}{R2}\\\frac{1}{Re}= \frac{1}{100}+\frac{1}{50}\\\frac{1}{Re}= \frac{3}{100}\\Re=\frac{100}{3} \,\,\Omega

By knowing this, we can estimate the total current through the circuit,:

Vs=I\,*\,(\frac{100}{3} +25)\\10=I\,*\,\frac{175}{3} \\I=\frac{30}{175} \,amps

So approximately 0.17  amps

and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:

V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V

So now we know that the potential drop across the parellel resistors must be:

10 V -  4.28 V = 5.72 V

and with this info, we can calculate the current through R1 using Ohm's Law:

I_1=\frac{V_1}{R_1} =\frac{5.72}{100} =0.0572\,\,amps

4 0
3 years ago
You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfo
dolphi86 [110]

Answer:

Explanation:

To convert gram / centimeter³ to kg / m³

gram / centimeter³

= 10⁻³ kg / centimeter³

= 10⁻³  / (10⁻²)³ kg / m³

= 10⁻³ / 10⁻⁶ kg / m³

= 10⁻³⁺⁶ kg / m³

= 10³ kg / m³

So we shall have to multiply be 10³ with amount in gm / cm³ to convert it into kg/m³

2.33 gram / cm³

= 2.33 x 10³ kg / m³ .

3 0
3 years ago
Which of the following tools measures weight? A balance A scale A cyclometer A graduated cylinder
Kazeer [188]
I'm pretty sure its a scale.
8 0
3 years ago
Two cars are traveling along perpendicular roads, car A at 40 mi/hr, car B at 60 mi/hr. At noon, when car A reaches the intersec
Serggg [28]

Answer:

\frac{dD}{dt} = -4 miles/hour

negative sign indicates that the distance is decreasing with time

Explanation:

Let at any time t after noon that is 12 p.m.  

distance traveled by car A = 40t

distance traveled by car B = 90-60t

then distance between the two cars at time t

D^2= (40t)^2+(90-60t)^2............1

also, at time 1 p.m.

distance D^2= (40\times1)^2+(90-60\times1)^2

D=50 Km

differentiating equation 1 w.r.t. t we get

2D\frac{dD}{dt}= 2\times40t\times40+2(90-60t)(-60)

put t= 1 and D= 50 we get

2\times50\frac{dD}{dt}= 3200\times1-3600\times1

\frac{dD}{dt} = -4 miles/hour

3 0
3 years ago
The process of reflection is most similar to _____.
Arte-miy333 [17]

Answer:

C.transmission

Explanation:

Scattering is everywhere

Absorption is to remove

3 0
3 years ago
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