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3 years ago

Identify the solute and solvent in a solution made from 15 mL of oxygen and 5 mL of helium.

Chemistry

1 answer:

Marina CMI [18]3 years ago

6 0

Answer:

Oxygen is solvent and Helium is solute.

Explanation:

Helium is a complety inert gas which do not react with other compounds whereas, oxygen can take part in chemical reaction with many compounds.

if we mix 15 mL of oxygen and 5mL of helium then the oxygen is the solvent and helium is solute.
In a mixture the compound with the greater volume is solvent and the compound with lwss volume is solute.
in this case, oxygen has greater volume than that of helium so oxygen is solute and helium is solvent here.

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5.15 Carbon steel (AISI 1010) shafts of 0.1-m diameter are heat treated in a gas-fired furnace whose gases are at 1200 K and pro

Sonja [21]

Answer:

The time required to reach the center line temperature of 800 K is t = 58 sec

Explanation:

Given data

D = 0.1 m

h = 100 $\frac{W}{m^{2}K }$

Specific heat for carbon steel (C) = 502.4 $\frac{J}{Kg K}$

Furnace temperature $T_ o$ = 1200 K

Final temperature T = 800 K

Initial temperature $T_i$ = 300 K

From lumped heat analysis

$\frac{T - T_o}{T_i -T_o} = e^({- \frac{6h}{\rho C D} } } ) t$ ------- (1)

$\frac{6h}{\rho CD} = \frac{(6)(100)}{(7850)(540)(0.1)}$

$\frac{6h}{\rho CD} = 0.001415$

Now from equation (1)

$\frac{800-1200}{300-1200} = e^{-0.001415t}$

㏑ 0.44 = -(0.001415 ) t

-(0.001415 ) t = - 0.82

t = 58 sec

Thus the time required to reach the center line temperature of 800 K is

t = 58 sec

6 0

4 years ago

How would the world be different if people were not aware of radioactive decay

allsm [11]

Answer:

everyone would die

Explanation:

if we did not know about it we would not do anything about it

6 0

3 years ago

When droplets of water in the atmosphere act like prisms the colord in sunlight undergo

Butoxors [25]

When droplets of water in the atmosphere act like prism the color in the sunlight undergo interferance, making rainbows. ( This is how rainbows form)

6 0

4 years ago

Read 2 more answers

Tris is a weak base. The basic form of tris can be written tris0 and the protonated (conjugate acid) form can be written tris. T

Arada [10]

Answer:

a) [Tris0] : [Tris] = 1 : 100

b) Range = 7.1 to 9.1

Explanation:

a) Calculation of ratio of the basic and the acidic forms of tris

pH of a buffer is calculate using Henderson-Hasselbalch equation

$pH = pKa+log\frac{Salt}{Acid}$

Conjugate acid of Tris dissociated as

$Tris \leftrightharpoons Tris0 + H^+$

For tris,

Salt or Basic form = tris0

Acid or Acidic form = Tris

pKa = 8.1

pH = 6.1

$pH = pKa+log\frac{Tris0}{Tris}$

$6.1 = 8.1+log\frac{Tris0}{Tris}$

$log\frac{Tris0}{Tris} = -2$

$\frac{Tris0}{Tris} = antilog (-2)$

$\frac{Tris0}{Tris} = 10^{-2}$

[Tris0] : [Tris] = 1 : 100

b) Range of Tris

Range of any buffer is:

From (pKa -1) to (pKa+1)

So, range of Tris is:

From (8.1 - 1) to (8.1 +1)

or from 7.1 to 9.1

8 0

3 years ago

In glycolysis, if glucose is labeled at the carbon 6 position (see page 1 for numbering of carbons in glucose) A) the carbon wit

Oliga [24]

Answer:

D) the carbon with the low-energy phosphate on it in 1,3 BPG is labeled.

Explanation:

Glycolysis has 2 phase (1) preparatory phase (2) pay-off phase.

(1) Preparatory phase

During preparatory phase glucose is converted into fructose-1,6-bisphosphate. Till this time the carbon numbering remains the same i.e. if we will label carbon at 6th position of glucose, its position will remian the same in fructose-1,6-bisphosphate that means the labeled carbon will still remain at 6th position.

When fructose-1,6-bisphosphate is further catalyzed with the help of enzyme aldolase it is cleaved into two 3 carbon intermediates which are glyceraldehyde 3-phosphate (GAP) and dihyroxyacetone phosphate (DHAP). In this conversion, the first three carbons of fructose-1,6-bisphosphate become carbons of DHAP while the last three carbons of fructose-1,6-bisphosphate will become carbons of GAP. It simply means that GAP will acquire the last carbon of fructose-1,6-bisphosphate which is labeled. Now the last carbon of GAP which has phosphate will be labeled.

(2) Pay-off phase

During this phase, GAP is dehydrogenated into 1,3-bisphosphoglycerate (BPG) with the help of enzyme glyceraldehyde 3-phosphate dehydrogenase. This oxidation is coupled to phosphorylation of C1 of GAP and this is the reason why 1,3-bisphosphoglycerate has phosphates at 2 positions i.e. at position 1 in which phosphate is newly added and position 3rd which already had labeled carbon.

It is pertinent to mention here that BPG has a mixed anhydride and the bond at C1 is a very high energy bond. In the next step, this high energy bond is hydrolyzed into a carboxylic acid with the help of enzyme phosphoglycerate kinase and the final product is 3-phosphoglycerate. Hence, the carbon with low energy phosphate i.e. the carbon at 3rd position remains labeled.

3 0

3 years ago