Answer:
Explanation:
An example of an intense aerobic activity would be running/ sprinting sprinting targets six specific muscle groups: hamstrings, quadriceps, glutes, hips, abdominals and calves. Sprinting is a total body workout featuring short, high-intensity repetitions and long, easy recoveries.
Answer:
for this problem, 2.5 = (5+2/2)-(5-2/2)erf (50×10-6m/2Dt)
It now becomes necessary to compute the diffusion coefficient at 750°C (1023 K) given that D0= 8.5 ×10-5m2/s and Qd= 202,100 J/mol.
we have D= D0exp( -Qd/RT)
=(8.5×105m2/s)exp(-202,100/8.31×1023)
= 4.03 ×10-15m2/s
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The average power is 20.3 kW
Explanation:
First of all, we calculate the work done on the car: the work-energy theorem states that the work done on the car is equal to the change in kinetic energy of the car, so we have

where
W is the work done
are the initial and final kinetic energy of the car
is the mass of the car
u = 0 is the initial velocity
v = 18.0 m/s is the final velocity
Substituting,

Now we can find the average power developed by the car's engine, which is given by

where
is the work done
t = 12.0 s is the time taken
Substituting,

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Answer:
T2 = 16327.5 N
Explanation:
T1 cos(25) = T2 cos(65)
200000 cos(45) = T2 cos(30)
T2 = 20000 x cos (45) / cos (30) = 16327.5 N