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Naily [24]
3 years ago
13

When you walk up to any substance, you can categorize the substance as a solid, liquid, or gas. You could further categorize the

substance as being a pure substance or a mixture, which you wouldn't know without more information. Assuming the substance is pure, what are 3 ways you could report the "amount" of substance in front of you
Chemistry
1 answer:
natima [27]3 years ago
8 0

Answer and Explanation:

In Chemistry, the quantity or amount of a pure substance is given by:

  1. <em>mass</em><em> (in grams)</em>
  2. <em>Volume </em><em>(in millilitres or litres)</em>
  3. <em>Moles </em><em>(mol) </em>

Inter-conversion of units is allowed based on defined units and constituent of the substance.

I believe this explanation would be helpful and easy to follow.

You might be interested in
Como hallar el numero de protones y el numero de electrones de un elemento
saw5 [17]

Answer:

Fácil, vas a la tabla periódica, y el número de protones, será el numero atómico, es decir, el que determina qué elemento es. Y para obtener el de electrones, deberás, restarle al numero másico el numero atómico, que es el número de protones y electrones en el elemento.

Explanation:

8 0
3 years ago
75 mL of water is added to a 360 mL solution of acetic acid with a concentration of 0.87 M. Determine the molarity of the new so
kramer

Answer:

The molarity of the new solution is 0.72 M

Explanation:

Step 1: Data given

Volume of the original solution = 360 mL =.360 L

Molarity = 0.87 M

We add 75 mL = 0.075 L

Step 2: Calculate moles

Moles = molarity * volume

Moles = 0.87 M * 0.360 L

Moles = 0.3132 moles

Step 3: Calculate new molarity

The number of moles stays constant

Molarity = moles / volume

Molarity = 0.3132 moles / (0.36+0.075)

Molarity = 0.3132 moles / 0.435 L

Molarity = 0.72 M

The molarity of the new solution is 0.72 M

3 0
3 years ago
When can I use ideal gas law?
Elis [28]
Answer:

The ideal gas law can be used in stoichiometry problems in which chemical reactions involve gases. Standard temperature and pressure (STP) are a useful set of benchmark conditions to compare other properties of gases. At STP, gases have a volume of 22.4 L per mole.
3 0
3 years ago
Given that you have 14.5 moles of n2, how many moles of h2 are theoretically needed to produce 30.0 moles of nh3 according to re
erastovalidia [21]

45 moles of H₂ are theoretically needed to produce 30.0 moles of NH₃

<h3>Further explanation</h3>

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

  • Mole

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³

Mole can also be sought if the amount of substance mass and its molar mass is known

\large{\boxed{\boxed{\bold{mol=\frac{mass}{molar\:mass}}}}

 

Reaction that happens :

N₂ +3H₂ ⇒ 2NH₃

mole N₂ : H₂ : NH₃ = 1 : 3 : 2

To produce 30.0 moles of NH₃,

  • H₂ needed :

mole~H_2~=~\frac{3}{2}\times~30~mole

mole H₂ = 45 mole

  • N₂ needed :

mole~N_2~=~\frac{1}{2}~\times~30

mole N₂ = 15 mole

So the minimum N₂ needed is: 15 mole

14.5 moles of N₂ can only produce NH₃ :

mole~NH_3~=~\frac{2}{1}~\times~14.5

mole NH₃ = 29 mole

<h3>Learn more </h3>

The mass of one mole of raindrops

brainly.com/question/5233234

moles of NaOH

brainly.com/question/4283309

moles of water you can produce

brainly.com/question/1405182

 

Keywords: mole,  NH₃, N₂, H₂

7 0
3 years ago
Read 2 more answers
How much energy is required to raise the temperature of 10.7 grams of gaseous helium from 22.1 °C to 39.4 °C ?
Rainbow [258]

Answer:

Q = 2640.96 J

Explanation:

Given data:

Mass of He gas = 10.7 g

Initial temperature = 22.1°C

Final temperature = 39.4°C

Heat absorbed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree. Specific heat capacity of He is 14.267 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 39.4°C - 22.1°C

ΔT = 17.3°C

Q = 10.7 g× 14.267 J/g.°C ×  17.3°C

Q = 2640.96 J

5 0
3 years ago
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