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notka56 [123]
3 years ago
11

A scientist discovers that an atom with a mass number of 14 contains eight electrons.

Chemistry
1 answer:
vesna_86 [32]3 years ago
6 0

its 8 im positive i had the same question

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What would happen if you used a warm washcloth if you had a fever.
aivan3 [116]
You will feel way better because in our class we learned that lukewarm baths are good for fevers and warm washcloths :)
3 0
3 years ago
How many moles are in 3.0g of A1203?
vfiekz [6]

Answer:

0.065 moles

Explanation:

4 0
3 years ago
What is the number of grams of N₂ (g) that contains 1.80 x 10^24 molecules?
svet-max [94.6K]

Answer:

83.69 gm

Explanation:

molar weight of N2 = 28

Find the number of moles then multiply by this

1.8 x10^24/ (6.022x10^23)   * 28 =83.69 gm

7 0
2 years ago
(a) if a sample containing 2.00 ml of nitroglycerin is detonated, how many total moles of gas are produced? (b) if each mole of
gregori [183]
Detonation of nitroglycerin: 

4C_3H_5N_3O_9  ------\ \textgreater \  12CO_2+6N_2+O_2+H_2O

<span>Mass nitroglycerin = 2.00 mL x 1.592 g/mL = 3.184 g 
</span>
Moles = mass / molar mass = 3.184<span> g/ 227.0872 g/mol = 0.01402
</span>
the ratio between nitroglycerin and Carbon dioxide is 4 : 12 
So, moles CO2 = 0.01402 x 12 / 4 =0.0420

the ratio between nitroglycerin and N2 is 4 : 6 
moles N2 = 0.01402 x 6 / 4 =0.0841

<span>the ratio between nitroglycerin and O2 is 4 : 1 </span>
moles O2 = 0.01402 x 1 / 4 = 0.0035

<span>the ratio between nitroglycerin and water is 4 : 1 </span>
<span>in the same way moles water = 0.005258 </span>

total moles = 0.0420 + 0.0841 + 0.0035 + 0.005258 = 0.130758

0.130758<span> x 55 = 5.78 L </span>

Mass N2 = 0.0841 mol x 28.0134 g/mol = 2.3548 g


6 0
2 years ago
A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Evgesh-ka [11]

Answer:

The answer to your question is   P2 = 0.78 atm

Explanation:

Data

Temperature 1 = T1 = 263°K                 Temperature 2 = T2 = 298°K

Volume 1 = V1 = 24 L                             Volume 2 = V2 = 35 L

Pressure 1 = P1 = 1                                  Pressure 2 = P2 = ?

Process

1.- To solve this problem use the Combined gas law

                          P1V1/T1 = P2V2/T2

-Solve for P2

                           P2 = P1V1T2 / T1V2

-Substitution

                          P2 = (1)(24)(298) / (263)(35)

-Simplification

                          P2 = 7152 / 9205

-Result

                          P2 = 0.777

   or                    P2 = 0.78 atm

5 0
3 years ago
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