The equation that we will use to solve these two questions is:
c = lambda * f where:
c is the speed f the wave
lambda is the wavelength of the wave
f is the frequency of the wave
Question 1:
we want to find f
c is assumed to be the speed of light = 3*10^8 m/sec
lambda = 5.6 * 10^10 cm = 560 * 10^6 meters
Substitute in the equation to get f as follows:
3*10^8 = 560*10^6*f
f = (3*10^8) / (560*10^6) = 0.5357 Hz
Question 2:
we want to find lambda
c is assumed to be the speed of light = 3*10^8 m/sec
f is given as 0.1096 Hz
Substitute in the equation to get lambda as follows:
3*10^8 = lambda * 0.1096
lambda = (3*10^8) / (0.1096) = 2.737226*10^9 meters
The higher concentrated solution is 0.250 mole LiCl dissolved in 250 ml of solution
( B).0.250mole of LiCl diluted in 250ml solution
<u>Explanation:</u>
<u>Procedure to find the intensity of the solution:</u>
To find the intensity of the solution, we have to use the following formula
M1V1=M2V2
250mL of a 0.500 M aqueous solution of LiCl is diluted with water
250 ml of a 0.250M aqueous solution of LiCl is diluted with water

Thus the PH level of a solution increases from ascending order, Therefore the Solution with 62.5M is a higher concentration than that of the solution with 125M.
3721 is 0.000003721 in meters
This picture sets a soothing scene, as the sunset lies over the trees. It is very calm outside because the wind is in no rush. It has to be winter because thy tree hath bare branches and the clouds settle down waiting for night. The moon is jealous because it can not create anything as beautiful.
HOPE THIS HELPED!