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adoni [48]
3 years ago
14

Which chemical in the atmosphere of Titan (a moon of Saturn) plays the same role that water plays on the Earth by producing "rai

n," "snow," and "ice" at the temperature encountered on Titan?
Chemistry
1 answer:
ololo11 [35]3 years ago
7 0

Answer:

Methane (CH₄)

Explanation:

Titan refers to the largest moon of the planet Saturn, comprising a very dense atmosphere. This moon is primarily comprised of nitrogen gas, which is similar to the conditions in earth. It is extremely cold having a temperature of about ₋180°C, as a result of which it is difficult for the liquid water to exist.

Acid rain is a type of precipitation that occurs in the earth and it results in the release of a certain amount of methane gas (CH₄). Similarly, there also occurs precipitation in Titan but it releases CH₄ instead of water.  This methane is responsible for the increasing amount of temperature.

Thus, methane is a chemical that is present int the Titan's atmosphere, and it plays a similar role as in earth, the water plays by forming snow, rain, and ice.

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The specific heat capacity of liquid ethanol is 2.42 J/gºC.
VladimirAG [237]
Hope it helps for you : )

8 0
2 years ago
Which does not affect chemical equilibrium
Amanda [17]
An inert gas will not react with either the reactants or the products, so it will have no effect on the product/reactant ratio, and therefore, it will have no effect on equilibrium.
5 0
3 years ago
Read 2 more answers
A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix
Alisiya [41]

Answer:

M_f=38.8\%

Explanation:

From the question we are told that:

Pressure P=747mmHg

Temperature T=298K

Volume V=11.1

Heat Produced Q=780kJ

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 n= (747/760) *11.1/ (0.0821*298)

 n=0.446mol

Therefore

 x+y=0.446

 x=0.446-y .....1

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

 x(889) + y(2220) = 760 ...... 2

Comparing Equation 1 and 2 and solving simultaneously

 x=0.446-y .....1

 x(889) + y(2220) = 760 ...... 2

 x=0.173

 y=0.273

Therefore

Mole fraction 0f Methane is mathematically given as

 M_f=\frac{x}{n}*100\%

 M_f=\frac{1.173}{0.446}*100\%

 M_f=38.8\%

7 0
3 years ago
What elements are being reduced and oxidized in this chemical formula?
dangina [55]

Answer: The element Na (Sodium) is getting oxidized and Hydrogen is getting reduced.

Explanation:

Oxidation reactions are the reactions in which addition of oxygen takes place.

Reduction reactions are the reactions in which loss of oxygen takes place.

For a given reaction:

2Na(s)+2H_2O(l)\rightarrow H_2(g)+2NaOH(aq.)

Sodium is getting oxidized because there is an addition of reaction with that element.

Hydrogen is getting reduced because there is a removal of oxygen with that element.

3 0
3 years ago
Which of the following would be a reasonable synthesis of CH3CH2CH2CH2OH?Group of answer choices
vampirchik [111]

Answer:

B. 1-Butene rightarrow (1) BH3: THF (2)H202, OH-

Explanation:

In the hydroboration of alkenes, an alkene is hydrated to form an alcohol with anti-Markovnikov orientation.

the reagent BH₃:THF is the way that borane is used in organic reactions. The BH₃ adds to the double bond of an alkene to form an alkyl borane. Peroxide hydrogen in basic medium oxidizes the alkyl borane to form an alcohol. Indeed, hydroboration-oxidation converts alkenes to alcohols by adding water through the double bond, with anti-Markovnikov orientation.

8 0
3 years ago
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