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4 years ago

A stream of negatively charged particles is called:

1 answer:

4 0

Cathode rays are a stream of negatively charged particles or electrons in vacuum tubes. They were first seen by Johann Hittorf in 1869. They are named since they are emitted by electrode or cathode. In order to release the electrons, the electrons should first be detached from the atoms of the cathode.

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Calculate the activity of KI, x, in the following electrochemical cell if the potential is +0.350 V. Ag|AgCl(s), NaCl(aq,a=0.1)|

Mkey [24]

Answer: The activity KI for the given electrochemical cell is 0.0310

Explanation:

The given chemical cell follows:

$Ag|AgCl(s),NaCl(aq.,a=0.1)||KI(aq,a=x)|I_2(s)|Pt$

Oxidation half reaction: $Ag(s)+Cl^-(aq.,)\rightarrow AgCl(s)+e^-;E^o_{AgCl/Cl^-}=0.22V$

Reduction half reaction: $\frac{1}{2}I_2(s)+e^-\rightarrow I^-(aq.);E^o_{I_2/I^-}=0.54V$

Net cell reaction: $Ag(s)+Cl^-(aq.)+\frac{1}{2}I_2(s)\rightarrow AgCl(s)+I^-(aq.)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.54-(0.22)=0.32V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{a_{I^-}}{a_{Cl^-}}$

where,

$E_{cell}$ = electrode potential of the cell = 0.350 V

$E^o_{cell}$ = standard electrode potential of the cell = +0.32 V

n = number of electrons exchanged = 1

$a_{Cl^-}=0.1$

$a_{I^-}=x$

Putting values in above equation, we get:

$0.350=0.32-\frac{0.059}{1}\times \log(\frac{x}{0.1})$

$x=0.0310$

Hence, the activity KI for the given electrochemical cell is 0.0310

5 0

3 years ago

The amount of space that matter takes up is its

Masja [62]

Answer:

i think volume

Explanation:

3 0

4 years ago

Read 2 more answers

The first person to introduce the idea of the continents moving around the surface of earth was...

Damm [24]

The answer would be Alfred Wegener

8 0

4 years ago

Determine the volume in liters occupied by 14g of nitrogen gas STP

stealth61 [152]

Molar mass N₂ = 28.0 g/mol

Number of moles:

n = mass / molar mass

n = 14 / 28.0

n = 0.5 moles

1 mole N₂ -------- 22,4 ( at STP)
0.5 mole N₂ ------- ?? Liters

L = 22.4 * 0.5 = 11,2 L

hope this helps!

8 0

4 years ago

Different between intermolecular and intra molecular dehydration

harkovskaia [24]

Answer: Intermolecular bonds are the forces between the molecules. Intramolecular are the forces within two atoms in a molecule.

Explanation:

4 0

3 years ago