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3 years ago

A car with a mass of 2.0×10^3 kg is traveling at 15m/s .what is the momentum of the car ?

1 answer:

7 0

Hello,

<span>A car with a mass of 2.0×10^3 kg is traveling at 15m/s. We need to find the momentum of the car. To do so, follow this formula:

p=mv

Where,

p = momentum
m = mass
v = </span>velocity

The cars mass is 2.0E3 and its velocity is 15m/s. Therefore:

p=2.0 x 10^3 *15 or 2000(15)

p=30000

Thus, the cars momentum is 30000 kg m/s

Faith xoxo

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evablogger [386]

6 meters is left because you subtract 12 meters from 6

5 0

3 years ago

A box has the dimensions of 50 cm × 30 cm × 15 cm, weighs 150 N, and is to be

nadezda [96]

The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

<h3>What is pressure?</h3>

The physical force used to apply pressure to an object is defined as such. Per square inch of an object, a force is applied perpendicularly to its surface. For pressure, the fundamental formula is F/A. (Force per unit area). The Pascal is the unit of pressure (Pa).

The four different types of pressure are absolute, atmospheric, differential, and gauge pressure. Have you ever noticed that when you use a straw to drink something, the air actually gets suked out? In reality, you're applying "Pressure" as you drink the beverage.

A box has the dimensions of 50 cm × 30 cm × 15 cm

Let each face be A, B and C

The weight of the box = 150 N

Formula for pressure is

P = F/A

To find out which face of the box can withstand a pressure of 0.25 N/cm

we need find the area of each face and find its pleasure

Face A = 50 cm × 30 cm

Area A = l × b

= 50 × 30

= 1500 cm²

Pressure A = 150/1500

= 0.1 N/cm³

0.25 > 0.1

The surface can definitively withstand the pressure of Face A

Face B = 30 cm × 15 cm

Area A = l × b

= 30 × 15

= 450 cm²

Pressure A = 150/450

= 0.3 N/cm³

0.25 < 0.3

The surface could not withstand the pressure of Face B

Face C = 50 cm × 15 cm

Area A = l × b

= 50 × 15

= 750 cm²

Pressure A = 150/750

= 0.2 N/cm³

0.25 > 0.2

The surface can definitively withstand the pressure of Face C

Thus, The surface can only withstand a pressure Face A (50cm × 30cm) and Face C (50cm × 15cm) as the surface can only withstand a pressure of 0.25 N/cm³.

Learn more about Pressure

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8 0

1 year ago

A man attaches a divider to an outdoor faucet so that water flows through a single pipe of radius 9.25 mm into four pipes, each

irinina [24]

Answer:

1.24 m/s

Explanation:

Metric unit conversion:

9.25 mm = 0.00925 m

5 mm = 0.005 m

The volume rate that flow through the single pipe is

$\dot{V} = vA = 1.45 * \pi * 0.00925^2 = 0.00039 m^3/s$

This volume rate should be constant and divided into the 4 narrower pipes, each of them would have a volume rate of

$\dot{V_n} = \dot{V} / 4 = 0.00039 / 4 = 9.74\times10^{-5} m^3/s$

So the flow speed of each of the narrower pipe is:

$v_n = \frac{\dot{V_n}}{A_n} = \frac{\dot{V_n}}{\pi r_n^2}$

$v_n = \frac{9.74\times10^{-5}}{\pi 0.005^2} = 1.24 m/s$

8 0

3 years ago

A 15 kg object and a 18 kg object are connected by a massless compressed spring and

MatroZZZ [7]

Hi there!

This is an example of a recoil collision.

Using the conservation of momentum:

$p_i = p_f$

The initial momentum is 0 kgm/s (objects start from rest), so:

$p_f = 0$

We are given that the 15 kg block has a velocity of 12 m/s to the left, so:

$m_1v_1' + m_2v_2' = 0 \\\\15(-12) + 18v_2' = 0 \\\\$

Solve for v2':

$18v_2' = 180 \\\\v_2' = \boxed{10 m/s}$

5 0

2 years ago

A block of aluminum with a volume of 10 cm3 is placed in a beaker of water filled to the brim. Water overflows. The same is done

mihalych1998 [28]

Answer:

a) Both blocks displace the same amount of water.

Explanation:

Specific gravity (S.G.) is a quantity that tells how much and object is submerged on water and is given by:

$S.G=\frac{\rho_{block}}{\rho_{fluid}}$

with ρ the densities

Density of water is $997 \frac{kg}{m^{3}}$ and density of aluminum is $2712 \frac{kg}{m^{3}}$

So:

$S.G=\frac{2712}{997}=2.72$

A S.G. value bigger than one means the object is totally submerged so the water displaced is equal to the volume of the cube.

For the lead (density = $11340\frac{kg}{m^{3}}$ ) block we're going to calculate specific gravity in this case:

$S.G=\frac{11340}{997}=11.37$

Again S.G gravity is bigger than 1, so the lead block is totally submerged too, that implies the volume of water displaced is the volume of the block, that is the same volume as the aluminum block, so a is the correct one.

7 0

3 years ago