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Margaret [11]
3 years ago
15

On a piece of paper, draw the structure of 3-heptyne. now describe the structure you have drawn:

Chemistry
2 answers:
mezya [45]3 years ago
8 0

Explanation:

The name alkyne which includes the letters "yne" means that there are three bonds attache to the carbon at the specified place. It is an unsaturated hydrocarbon because it contains a triple bond.

For example, 3-heptyne is a seven membered carbon chain with a triple bond at carbon 3.

The formula of 3-heptyne is as follows.

                   C_{7}H_{12}

Tems11 [23]3 years ago
6 0
<span><span>Molecular Formula is given as : <span>C7H12
</span></span><span>Average mass is = 96.170 Da
</span><span>Monoisotopic mass is = 96.093903 Da
</span><span>ChemSpider ID is = 68268

Structure :
</span></span><span>1) Straight chain of 7 carbons
</span>2) T<span>riple bond between carbon 3 and Carbon 4

</span><span>Carbon 2, Carbon 3, Carbon 4, and Carbon 5 are sketched collinearly.</span>

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Given 8.25 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
mash [69]

Answer:

              10.87 g of Ethyl Butyrate

Solution:

The Balance Chemical Equation is as follow,

   H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH  →  H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O

According to equation,

    88.11 g (1 mol) Butanoic Acid produces  =  116.16 g (1 mol) Ethyl Butyrate

So,

           8.25 g Butanoic Acid will produce  =  X g of Ethyl Butyrate

Solving for X,

                      X =  (8.25 g × 116.16 g) ÷ 88.11 g

                      X =  10.87 g of Ethyl Butyrate

8 0
3 years ago
You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accurately to 4 significant fi
zmey [24]

Answer:

Average density for method A = 2.4 g/cm³

Average density for method B = 2.605 g/cm³

Explanation:

In order to calculate the average density for each method, we need to add the data for each method, and then divide the result by the number of measurements (in this case is 4 for both methods):

  • For Method A:

Σ = 2.2 + 2.3 + 2.7 + 2.4 = 9.6

Average = 9.6/4 = 2.4 g/cm³

  • For Method B:

Σ = 2.603 + 2.601 + 2.605 + 2.611 = 10.420

Average = 10.420/4 = 2.605 g/cm³

5 0
3 years ago
Write ionic equations for the following:<br> HCl(aq) + KOH(aq) → KCl(aq) + H2O(l)
vodomira [7]

Answer:

HCl(aq) + KOH(aq) ===> H2O(l) + KCl(aq)

Note the stoichiometry of the balanced equations shows us that HCl and KOH react in a 1:1 mole ratio. So, let us find moles of HCl and moles of KOH that are present:

moles HCl = 250.0 ml x 1 L/1000 ml x 0.25 mol/L = 0.06250 moles HCl

moles KOH = 200.0 ml x 1 L/1000 ml x 0.40 mol/L = 0.0800 moles KOH

You can see that there are more moles of KOH than there are of HCl, meaning that KOH is in excess and after neutralizing all of the HCl, the solution will be left with excess KOH making the pH > 7 = BASIC

4 0
2 years ago
BRAINLIEST AND POINTS!!
umka21 [38]

Answer:

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Explanation:

4 0
3 years ago
Read 2 more answers
The rate constant k for a certain reaction is measured at two different temperatures:
bogdanovich [222]

Answer:

Ea=5.5 Kcal/mole

Explanation:

Let rate constant are K_1  and K_2  at temperature T_1  and T_2

By using Arrhenius equation at two different two different temperature,

Log K_1/K_2 =E_a/2.303R*(1/T_2 -1/T_2 );T_1=273+376=649K  ;K_1=4.8*10^8;T_2=273+280=553K  ;K_2=2.3*10^8;R=2 cal/(mole.K);Log (4.8*10^8)/(2.3*10^8 )=E_a/2.303R*(1/553K-1/649); Log 4.8/2.3=E_a/2.303R*96/358897 ;0.32=E_a/2.303R*96/358897;E_a=(0.32*2.303R*358897)/96;  

By putting value of R=2 cal/mole.K

E_a=5510.265cal/mole;

By rounding off upto 2 significant figure;

E_a=5.5Kcal/mole;

8 0
3 years ago
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