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Paul [167]
2 years ago
11

Which of the following surfaces reflects the most light

Physics
2 answers:
Svetlanka [38]2 years ago
8 0

Answer:C

Explanation:

The best reflecting surface is a mirror or a polished surface.

Aluminum is polished better than any of them above option

Gre4nikov [31]2 years ago
3 0

Answer:

D

Explanation:

it could be the yellow cloth but we see are shadow on the sidewalk most of the time and shadows are made from reflecting light so your answer should be D

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A wagon has a mass of 100 grams and an
olga2289 [7]

Answer:

Net force on the wagon is 200 N

Explanation:

As we know by Newton's II law that net force on the system of mass is given as product of mass and acceleration

Here we know that

mass = 100 kg

a = 2 m/s/s

now we have

F = ma

F = (100)(2)

F = 200 N

3 0
3 years ago
A light ray is striking the surface of Earth. Which factor would make the light ray more likely to be absorbed than reflected? l
Vladimir [108]

Answer:

B

Explanation:

Trust

5 0
3 years ago
Read 2 more answers
An unstable particle at rest breaks up into two fragments of unequal mass. The mass of the lighter fragment is equal to 2.90 ✕ 1
motikmotik

Answer:

The speed of the heavier fragment is 0.335c.

Explanation:

Given that,

Mass of the lighter fragment M_{l}=2.90\times10^{-28}\ kg

Mass of the heavier fragment M_{h}=1.62\times10^{-27}\ Kg

Speed of lighter fragment = 0.893c

We need to calculate the speed of the heavier fragment

Let v is the speed of the second fragment after decay

Using conservation of relativistic momentum

0=\drac{m_{1}v_{1}}{\sqrt{1-\dfrac{v_{1}^2}{c^2}}}-\drac{m_{2}v_{2}}{\sqrt{1-\dfrac{v_{1}^2}{c^2}}}

\drac{m_{1}v_{1}}{\sqrt{1-\dfrac{v_{1}^2}{c^2}}}=\drac{m_{2}v_{2}}{\sqrt{1-\dfrac{v_{1}^2}{c^2}}}

\dfrac{2.90\times10^{-28}\times0.893c}{\sqrt{1-(0.893)^2}}=\dfrac{1.62\times10^{-27}v_{2}}{\sqrt{1-\dfrac{v_{2}^2}{c^2}}}

\dfrac{v_{2}}{\sqrt{1-\dfrac{v_{2}^2}{c^2}}}=\dfrac{2.90\times10^{-28}\times0.893c}{1.62\times10^{-27}\times0.45}

\dfrac{v_{2}}{\sqrt{1-\dfrac{v_{2}^2}{c^2}}}=0.355c

\dfrac{v_{2}}{1-\dfrac{v_{2}^{2}}{c^2}}=(0.355c)^2

\dfrac{1-\dfrac{v_{2}^2}{c^2}}{v_{2}^2}=\dfrac{1}{(0.355c)}

\dfrac{1}{v_{2}^2}-\dfrac{1}{c^2}=\dfrac{1}{(0.355c)^2}

\dfrac{1}{v_{2}^2}=\dfrac{1}{c^2}+\dfrac{1}{0.126c^2}

\dfrac{1}{v_{2}^2}=\dfrac{1}{c^2}(1+\dfrac{1}{0.126})

\dfrac{1}{v_{2}^2}=\dfrac{8.93}{c^2}

v_{2}^2=\dfrac{c^2}{8.93}

v_{2}=0.335c

Hence, The speed of the heavier fragment is 0.335c.

7 0
3 years ago
A particle moves at a constant speed in a circular path with a radius of r=2.06 cm. If the particle makes four revolutions each
nataly862011 [7]

The centripetal acceleration is 13.0 m/s^2

Explanation:

For an object in uniform circular motion, the centripetal acceleration is given by

a=\frac{v^2}{r}

where

v is the speed of the object

r is the radius of the circle

The speed of the object is equal to the ratio between the length of the circumference (2\pi r) and the period of revolution (T), so it can be rewritten as

v=\frac{2\pi r}{T}

Therefore we can rewrite the acceleration as

a=\frac{4\pi^2 r}{T^2}

For the particle in this problem,

r = 2.06 cm = 0.0206 m

While it makes 4 revolutions each second, so the period is

T=\frac{1}{4}s = 0.25 s

Substituting into the equation, we find the acceleration:

a=\frac{4\pi^2 (0.0206)}{0.25^2}=13.0 m/s^2

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

8 0
3 years ago
The gravitational field at the Moon in N/kg due to the Earth is approximately (G = 6.67 × 10-11 N m2/kg2, the mass of the Earth
rosijanka [135]

Answer:

F = 2.69 10⁻³ m   [ N]

Explanation:

This exercise asks to calculate the gravitational field of the Earth on the lunar surface, let's use the universal gravitation law

          F = G m M / r²

where m is the mass of the body, M the mass of the Earth and r the distance between the Earth and the Moon

         F = (G M / r²) m

         F = (6.67 10⁻¹¹ 5.98 10²⁴ / (3.85 10⁸)² ) m

         F = 2.69 10⁻³ m   [ N]

This force is directed from the Moon towards the Earth, therefore it reduces the weight of the body

8 0
3 years ago
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