Both products will start to cancel the acidity and how strong the base is if they are mixed. If the acid is stronger than the base then it will be an acidic product and visa versa if the base is stronger than the acid.
Answer:
The answer is B
Explanation:
The answer is B because representative particles can only be atoms.
Answer:
9.6 moles O2
Explanation:
I'll assume it is 345 grams, not gratis, of water. Hydrogen's molar mass is 1.01, not 101.
The molar mass of water is 18.0 grams/mole.
Therefore: (345g)/(18.0 g/mole) = 19.17 or 19.2 moles water (3 sig figs).
The balanced equation states that: 2H20 ⇒ 2H2 +02
It promises that we'll get 1 mole of oxygen for every 2 moles of H2O, a molar ratio of 1/2.
get (1 mole O2/2 moles H2O)*(19.2 moles H2O) or 9.6 moles O2
The pH of a solution is 9.02.
c(HCN) = 1.25 M; concentration of the cyanide acid
n(NaCN) = 1.37 mol; amount of the salt
V = 1.699 l; volume of the solution
c(NaCN) = 1.37 mol ÷ 1.699 l
c(NaCN) = 0.806 M; concentration of the salt
Ka = 6.2 × 10⁻¹⁰; acid constant
pKa = -logKa
pKa = - log (6.2 × 10⁻¹⁰)
pKa = 9.21
Henderson–Hasselbalch equation for the buffer solution:
pH = pKa + log(cs/ck)
pH = pKa + log(cs/ck)
pH = 9.21 + log (0.806M/1.25M)
pH = 9.21 - 0.19
pH = 9.02; potential of hydrogen
More about buffer: brainly.com/question/4177791
#SPJ4
Answer:
Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃
The coefficients are: 1, 6, 3, 2
Explanation:
__Fe₂(SO₄)₃ + __KOH —> __K₂SO₄ + __Fe(OH)₃
To determine the correct coefficients, we shall balance the equation. This can be obtained as follow:
Fe₂(SO₄)₃ + KOH —> K₂SO₄ + Fe(OH)₃
There are 2 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 2 before Fe(OH)₃ as shown below:
Fe₂(SO₄)₃ + KOH —> K₂SO₄ + 2Fe(OH)₃
There are 6 atoms of OH on the right side and 1 atom on the left side. It can be balance by writing 6 before KOH as shown below:
Fe₂(SO₄)₃ + 6KOH —> K₂SO₄ + 2Fe(OH)₃
There are 6 atoms of K on the left side and 2 atoms on the right side. It can be balance by writing 3 before K₂SO₄ as shown below:
Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃
Now, the equation is balanced.
Therefore, the coefficients are: 1, 6, 3, 2
