Given the balanced ionic equation representing a reaction:

What is the boiling point elevation constant, Kb, of diethyl ether if 38.2 g of the nonelectrolyte benzophenone, C6H5COC6H5, dis

kakasveta [241]

Answer: the boiling point elevation constant is $1.73^0C/m$

Explanation:

Elevation in boiling point is given by:

$\Delta T_b=i\times K_b\times m$

$\Delta T_b=T_b-T_b^0=$ = Elevation in boling point

i= vant hoff factor = 1 (for non electrolyte)

$K_b$ =boiling point constant = ?

m= molality

$\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (diethylether)= 330 g = 0.33 kg

Molar mass of solute (benzophenone)= 182 g/mol

Mass of solute (benzophenone) = 38.2 g

$(35.7-34.6)^0C=1\times K_b\times \frac{38.2g}{182g/mol\times 0.33kg}$

$K_b=1.73^0C/m$

Thus the boiling point elevation constant is $1.73^0C/m$

3 0

3 years ago

What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chem

Ainat [17]

Answer: 0.002 M

Explanation:

The balanced chemical equation for ionization of $H_2SO_4$ in water is:

$H_2SO_4\rightarrow 2H^++SO_4^{2-}$

According to stoichiometry :

1 mole of $H_2SO_4$ ionizes to give =2 mole of $H^+$ ions

0.001 mole of $H_2SO_4$ ionizes to give = $\frac{2}{1}\times 0.001=0.002$ mole of $H^+$ ions

Thus $H^+$ of a solution of 0.001 M aqueous sulfuric acid is 0.002 M

4 0

3 years ago

The compound magnesium iodide is a strong electrolyte write the reaction when solid magnesium iodide is put into water

mestny [16]

The reaction for magnesium iodide when put into water is as below

MgI2(s) → Mg^2+(aq) + 2I^-(aq)

when magnesium iodide but into water it dissociate/ ionize completely into Mg^2+ and 2l^- ions. Magnesium iodide dissociate/ionize completely because magnesium iodide is a strong electrolyte which dissociate/ ionize completely into their ions when it is put into water .

7 0

3 years ago

Occupational Safety and Health Administration has set the limit on the maximum percentage of carbon dioxide (CO2) in air a worke

Lyrx [107]

Answer:

The minimum rate of fresh air in the room is 176 moles/min

Explanation:

High exposure of CO₂ has health effects as headaches, increased heart rate, elevated blood pressure, coma, asphyxia, convulsions, etc.

0,500 mole% of CO₂ in air means 0,500 moles of CO₂ per 100 moles of air

As the rate of sublimation of CO₂ is 0,880, the minimum rate of fresh air in the room must be:

$\frac{0,500 moles CO_{2}}{100 moles Air} = \frac{0,880 moles CO_{2}/min}{X}$

X = <em>176 moles of Air/min</em>

I hope it helps!

4 0

3 years ago

Please Help me on this question

kirza4 [7]

Acids: taste sour, has a pH less than 7
bases: tastes bitter, has a pH greater than 7

6 0

3 years ago