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3 years ago

What is the resistance of a light bulb if a potential difference of 120 V will produce a current of 0.5 A in the bulb?

Physics

2 answers:

Yakvenalex [24]3 years ago

6 0

Explanation:

Ohm's law:

V = IR

120 V = (0.5 A) R

R = 240 Ω

Damm [24]3 years ago

3 0

Answer:

The resistance of alight bulb is 240 ohms.

Explanation:

Given that,

Potential difference of a light bulb, V = 120 V

Current produced in the light bulb, I = 0.5 A

We need to find the resistance of the light bulb. It can be calculated using Ohm's law. It is given by :

V = IR

$R=\dfrac{V}{I}$

$R=\dfrac{120\ V}{0.5\ A}$

R = 240 ohms

So, the resistance of alight bulb is 240 ohms. Hence, this is the required solution.

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Answer:

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Explanation:

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Divide both side by 23

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Divide both side by Cos θ

Sine θ /Cos θ = 1.5531

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Sine θ /Cos θ = Tan θ

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Tan θ = 1.5531

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