All categories

3 years ago

What is the resistance of a light bulb if a potential difference of 120 V will produce a current of 0.5 A in the bulb?

Physics

2 answers:

Yakvenalex [24]3 years ago

6 0

Explanation:

Ohm's law:

V = IR

120 V = (0.5 A) R

R = 240 Ω

Damm [24]3 years ago

3 0

Answer:

The resistance of alight bulb is 240 ohms.

Explanation:

Given that,

Potential difference of a light bulb, V = 120 V

Current produced in the light bulb, I = 0.5 A

We need to find the resistance of the light bulb. It can be calculated using Ohm's law. It is given by :

V = IR

$R=\dfrac{V}{I}$

$R=\dfrac{120\ V}{0.5\ A}$

R = 240 ohms

So, the resistance of alight bulb is 240 ohms. Hence, this is the required solution.

You might be interested in

The combined electrical resistance R of two resistors R_1 and R_2, connected in parallel, is given by 1/R = 1/R_1 + 1/R_2 where

Orlov [11]

Answer:

$0.6\Omega/s$

Explanation:

We are given that

$R_1=150\Omega$

$R_2=75\Omega$

$\frac{dR_1}{dt}=1\Omega/s$

$\frac{dR_2}{dt}=1.5\Omega/s$

We have to find the rate at which R is changing.

In parallel

$\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}$

Using the formula

$\frac{1}{R}=\frac{1}{50}+\frac{1}{75}=\frac{3+2}{150}=\frac{5}{150}=\frac{1}{30}$

$R=30\Omega$

$-\frac{1}{R^2}\frac{dR}{dt}=-\frac{1}{R^2_1}\frac{dR_1}{dt}-\frac{1}{R^2_2}\frac{dR_2}{dt}$

$\frac{1}{R^2}\frac{dR}{dt}=\frac{1}{R^2_1}\frac{dR_1}{dt}+\frac{1}{R^2_2}\frac{dR_2}{dt}$

Substitute the values

$\frac{1}{900}\frac{dR}{dt}=1\times\frac{1}{2500}+1.5\times\frac{1}{(75)^2}$

$\frac{dR}{dt}=900(\frac{1}{2500}+\frac{1.5}{5625}$

$\frac{dR}{dt}=0.6\Omega/s$

7 0

3 years ago

Use complete sentences to differentiate between acids and bases on the basis of their behavior when dissolved in water Give an e

grigory [225]

Explanation:

An acid is a substance that interacts with water to produce excess hydroxonium ions, H₃O⁺ in an aqueous solution.

The hydroxonium ions formed by the chemical bonding between the oxygen of water molecules and the protons released by the acid due to its excess ionization.

For example:

HCl + H₂O ⇄ H₃O⁺ + Cl⁻

acid water hydroxonium chloride

A base is a substance that interacts with water to yield excess hydroxide ions, OH⁻ in an aqueous solutions:

NH₃ + H₂O ⇄ NH₄⁺ + OH⁻

Ammonia water ammonium hydroxide

These explanations are based on the arrhenius theory.

learn more:

Bronsted-lowry theory brainly.com/question/4083753

Acid reaction brainly.com/question/5273689

#learnwithBrainly

4 0

2 years ago

A major league baseball has a mass of 0.145 kg.

galben [10]

The momentum of the ball when it hits the ground is 4.89 kg.m/s.

The given parameters;

<em>mass of the baseball, m = 0.145 kg</em>
<em>height of fall of the ball, h = 58 m</em>

The final velocity of the ball when it hits the ground is calculated as follows;

$v_f ^2 = v_0^2 + 2gh\\\\v_f^2 = 0 + 2gh\\\\v_f^2 = 2gh\\\\v_f = \sqrt{2gh} \\\\v_f = \sqrt{2\times 9.8 \times 58}\\\\v_f = 33.72 \ m/s$

The momentum of the ball when it hits the ground is calculated as follows;

P = mv

P = 0.145 x 33.72

P = 4.89 kg.m/s

Thus, the momentum of the ball when it hits the ground is 4.89 kg.m/s.

Learn more here:brainly.com/question/22035809

6 0

2 years ago

A planet has a mass of 5.68 x 1026 kg and a radius of 6.03 x 107 m. What is the weight of a 65.0 kg person on the surface of thi

Paul [167]

To solve this problem, we must know the gravitational force of the planet. The equation would be,

$F=G \frac{ m_{1} m_{2} }{ r^{2} }$

This would calculate the force between two objects with masses m1 and m2 and the gravitational constant, G, is 6.67 x 10^-11 m3 s-2 kg-1 and with r as the distance between the objects.

Thus,

F = (6.67 x 10^-11 m3 s-2 kg-1) * (5.68 x 10^26 kg) * (65 kg) * ((1/6.03 x 10^7 m)^2)

F = 678 kg/s^2 or 678 N

Answer is letter B.

4 0

3 years ago

Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.55 μC charge and flies due west at a speed of

Illusion [34]

Answer:

3.014 x 10⁻⁸ N

Explanation:

q = magnitude of charge on the supersonic jet = 0.55 μC = 0.55 x 10⁻⁶ C

v = speed of the jet = 685 m/s

B = magnitude of magnetic field in the region = 8 x 10⁻⁵ T

θ = angle between the magnetic field and direction of motion = 90

magnitude of the magnetic force is given as

F = q v B Sinθ

F = (0.55 x 10⁻⁶) (685) (8 x 10⁻⁵) Sin90

F = 3.014 x 10⁻⁸ N

6 0

2 years ago