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Serga [27]
3 years ago
13

What is the resistance of a light bulb if a potential difference of 120 V will produce a current of 0.5 A in the bulb?

Physics
2 answers:
Yakvenalex [24]3 years ago
6 0

Explanation:

Ohm's law:

V = IR

120 V = (0.5 A) R

R = 240 Ω

Damm [24]3 years ago
3 0

Answer:

The resistance of alight bulb is 240 ohms.

Explanation:

Given that,

Potential difference of a light bulb, V = 120 V

Current produced in the light bulb, I = 0.5 A

We need to find the resistance of the light bulb. It can be calculated using Ohm's law. It is given by :

V = IR

R=\dfrac{V}{I}

R=\dfrac{120\ V}{0.5\ A}

R = 240 ohms

So, the resistance of alight bulb is 240 ohms. Hence, this is the required solution.

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