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Serga [27]
3 years ago
13

What is the resistance of a light bulb if a potential difference of 120 V will produce a current of 0.5 A in the bulb?

Physics
2 answers:
Yakvenalex [24]3 years ago
6 0

Explanation:

Ohm's law:

V = IR

120 V = (0.5 A) R

R = 240 Ω

Damm [24]3 years ago
3 0

Answer:

The resistance of alight bulb is 240 ohms.

Explanation:

Given that,

Potential difference of a light bulb, V = 120 V

Current produced in the light bulb, I = 0.5 A

We need to find the resistance of the light bulb. It can be calculated using Ohm's law. It is given by :

V = IR

R=\dfrac{V}{I}

R=\dfrac{120\ V}{0.5\ A}

R = 240 ohms

So, the resistance of alight bulb is 240 ohms. Hence, this is the required solution.

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A river is flowing south at a rate of 3 m/s. Steven can roe directly across the river if he aims the raft 30 degrees. What rate
levacccp [35]

Answer:

Steven has to row at a speed to reach the same horizontal spot at the other side of the river is, V = 6 m/s

Explanation:

Given data,

The river flowing south at the rate, v = 3 m/s

To reach the other side directly across the river, he aims the raft, Ф = 30°

The speed of his raft across the river is given by the formula,

                                          V = v / Sin Ф

                                             = 3 / Sin 30°

                                              = 6 m/s

Steven has to row at a speed to reach the same horizontal spot at the other side of the river is, V = 6 m/s

3 0
3 years ago
In the simulation above, as the projectile travels upward, how does the vertical velocity change? Question 9 options:
enot [183]

Answer:

Vertical velocity decreases.

Explanation:

The motion of the ball is a projectile ball, which consists of two independent motions:

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In the vertical motion, there is a constant acceleration directed downward: this means that the vertical velocity decreases as the ball goes higher. In fact, it decreases following the equation

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evablogger [386]
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3 years ago
In a solution, the solvent is present in the larger amount. <br> A True <br> B False
lana [24]
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8 0
3 years ago
What is the temperature of a 3.72 mm cube (e=0.288) that radiates 56.6 W?
blsea [12.9K]

Answer:

The temperature is 2541.799 K

Explanation:

The formula for black body radiation is given by the relation;

Q = eσAT⁴

Where:

Q = Rate of heat transfer 56.6

σ = Stefan-Boltzman constant = 5.67 × 10⁻⁸ W/(m²·k⁴)

A = Surface area of the cube = 6×(3.72 mm)² = 8.3 × 10⁻⁵ m²

e = emissivity = 0.288

T = Temperature

Therefore, we have;

T⁴ = Q/(e×σ×A) = 56.6/(5.67 × 10⁻⁸ × 8.3 × 10⁻⁵ × 0.288) = 4.174 × 10¹⁴ K⁴

T  =  2541.799 K

The temperature = 2541.799 K.

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3 years ago
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